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3 years ago

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can someone help me.Bob made 15 basketball shots in 6 seconds and then he ha 34 seconds left in does 34 seconds he made 85 baske

tball shots.what they are asking is to show my work on how i could get 84.so what can be an equation that gives me that.

1 answer:

Anton [14]3 years ago

3 0

You can add any number like 42 plus 42 gives you 84

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What is the equation of the line that passes through the point (−8,3) and has a slope of -1/4?

tensa zangetsu [6.8K]

Answer:

y=-1/4x+1

Step-by-step explanation:

so here are my steps after plugging in the numbers:

y-3=-1/4(x+8)

y-3=-1/4x-2

y=-1/4x+1

6 0

3 years ago

A rectangular garden must have a perimeter of 155 feet and an area of at least 1400 square feet. Describe the possible lengths o

snow_lady [41]

Answer:

Step-by-step explanation:

Perimeter of a garden = 2(L+W)

Area of the gerden = LW

L is the length

W is the width

Given

Perimeter = 155ft

Area = 1400ft²

Substitute

1400 = LW

155 = 2L+2W

from 1;

W = 1400/L

Substitute into 2;

155 = 2L + 2(1400/L)

155 = 2L + 2800/L

155L = 2L² + 2800

2L²-155L + 2800 = 0

Factorize

L = 155±√155²-4(2)(2800)/4

L = 155±√24025-22400/4

L = 155±√1625/4

L = L = 155±40.31/4

L = 194.31/4

L = 48.82 feet and;

L = 155-40.31/4

L = 28.67ft

Hence the approximate length of the garden is at least 28.67 feet and at most 48.82 feet.

6 0

3 years ago

Rico wants to find the distance between the points (-2,-3) and (2,-5) his work is shown.|-3| + |-5| = 3+5 = 8the distance is 8 u

tino4ka555 [31]

Answer:

Riko is wrong

Step-by-step explanation:

To find the distance of two point, we use the following formula:

A (x1, y1)

B (x1, y2)

AB = $\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }$

In this situation, we have:

A (-2,-3)

B (2,-5)

So the distance is: $\sqrt{(2 - (-2))^{2} + (-5 - (-3))^{2} }$ = $\sqrt{4^{2} + 8^{2} }$ = $\sqrt{80} = 4\sqrt{5}$

Hope it will find you well.

5 0

3 years ago

Read 2 more answers

6(8x -2)<br><br> plz help me...

baherus [9]

Answer: 48x-12

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

An analog signal with a bandwidth of 36MHz is sampled at a frequency (fs) of 36,000,000 samples per second during the ADC (analo

Elza [17]

Answer:

The signal would have experienced aliasing.

Step-by-step explanation:

Given that:

the bandwidth of the signal $f_m$ = 36MHz

= 36 × 10⁶ Hz

The sampling frequency $f_s$ = 36 × 10⁶ Hz

Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.

Therefore, according to the Nyquist criteria;

Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.

∴

By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;

Then,

$f_s \geq 2f_m$

∴

The signal would have experienced aliasing.

4 0

3 years ago