5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10
Answer:
48 cubic yard
Step-by-step explanation:
![volume \: of \: pyramid \\ = area \: of \: base \times height \\ = {4}^{2} \times 3 \\ = 16 \times 3 \\ = 48 \: {yard}^{3} \\](https://tex.z-dn.net/?f=volume%20%5C%3A%20of%20%5C%3A%20pyramid%20%5C%5C%20%20%3D%20area%20%5C%3A%20of%20%5C%3A%20base%20%5Ctimes%20height%20%5C%5C%20%20%3D%20%20%7B4%7D%5E%7B2%7D%20%20%5Ctimes%203%20%5C%5C%20%20%3D%2016%20%5Ctimes%203%20%5C%5C%20%20%3D%2048%20%5C%3A%20%20%7Byard%7D%5E%7B3%7D%20%20%5C%5C%20)
The answer to your question is the inequality sign.
It’s D that is the answer
Answer:
The number of liters of 25% acid solution = x = 160 liters
The number of liters of 40% acid solution = y = 80 liters
Step-by-step explanation:
Let us represent:
The number of liters of 25% acid solution = x
The number of liters of 40% acid solution = y
Our system of Equations =
x + y = 240 liters....... Equation 1
x = 240 - y
A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution.
25% × x + 40% × y = 240 liters × 30%
0.25x+ 0.4y = 72...... Equation 2
We substitute 240 - y for x in Equation 2
0.25(240 - y)+ 0.4y = 72
60 - 0.25y + 0.4y = 72
Collect like terms
- 0.25y + 0.4y = 72 - 60
0.15y = 12
y = 12/0.15
y = 80 Liters
Solving for x
x = 240 - y
x = 240 liters - 80 Liters
x = 160 liters
Therefore,
The number of liters of 25% acid solution = x = 160 liters
The number of liters of 40% acid solution = y = 80 liters