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3 years ago

What is the y coordinate of the point that divides the

Mathematics

1 answer:

svet-max [94.6K]3 years ago

6 0

Answer:

the y coordinate is 5

Step-by-step explanation:

In the figure attached, the directed line segment is shown.

J is located at (-3, 1) and K is located at (-8, 11)

run: x2 -x1 = -8 - (-3) = -5

rise: y2 - y1 = 11 - 1 = 10

Taking J as reference, the coordinate of the point that divides the directed line segment from J to k into a ratio of 2:3 is:

c = 2/(2+3) = 0.4

(x1 + c*run, y1 + c*rise)

(-3 + 0.4*-5, 1+0.4*10)

(-5, 5)

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On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl

worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

<span>With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:</span>

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

<span>Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.</span>

8 0

2 years ago

Please Hurry! What is the solution to log2_(9x)-log2_3=3?

brilliants [131]

Answer:

$log_{2}(9x) - log_{2}(3) = 3 \\ 3 = log_{2}(8) or log_{2}( {2}^{3} ) \\ log_{2}( \frac{9x}{3} ) = log_{2}(8) \\ \frac{9x}{3} = 8 \\ 9x = 8 \times 3 \\ 9x = 24 \\ x = \frac{24}{9} \\ x = \frac{8}{3} \\ x = 2 \times \frac{2}{3}$

6 0

3 years ago

Read 2 more answers

Describe the transformations that will map triangle A to triangle B and illustrate the similarity between the two triangles.

Rus_ich [418]

Honestly I’m not for sure but I’m think it’s either a or b

6 0

2 years ago

Read 2 more answers

A right angled triangle has sides of length 9cm, 12cm and 15cm. Calculate its area in square centimetres.

Dmitriy789 [7]

The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.

The formula to calculate the area of a right triangle is given by:

Area of Right Triangle, A = (½) × b × h square units

Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.

We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.

Given sides of the triangle:

a=9cm

b=12cm

c=15cm

From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.

∴Area = $\frac{1}{2}$ x 9 x 12

= 54 $cm^{2}$

5 0

11 months ago

Hey I’m struggling with number 13 so please show your work. Thx

Dafna11 [192]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

Because $\frac{3}{5}$ is being multiplied by S, we can divide $\frac{3}{5}$ from both sides of the equation. This will give us:

$\frac{1}{4}$ ÷ $\frac{3}{5}$

But, that looks a bit hectic. Instead of dividing, you can multiply by the reciprocal (which is essentially how to divide fractions). So, instead of $\frac{1}{4}$ ÷ $\frac{3}{5}$ , you get:

$\frac{1}{4}$ × $\frac{5}{3}$

When multiplying fractions, remember you can just multiply straight across-- numerator x numerator, then denominator x denominator.

By doing that, you get the fraction $\frac{5}{12}$

$\frac{5}{12}$ cannot be simplified any more, so S= $\frac{5}{12}$ is your answer :)

I hope this helps

6 0

3 years ago