There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
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brainly.com/question/21405634
Answer: b. 51 - 3
Step-by-step explanation:
Given, Easha has 3 less than 5 times the number of quarters (I) that Isabelle has.
Here I is the number of quarters that Isabelle has.
Then, as per given,
Number of quarters Easha has = 5 ( number of quarters that Isabelle has) -3
= 5I-3
Hence, the expression shows the number of quarters Easha has is "5I-3"
So the correct option is b.
You divide 15 by 2 (D is the answer)
Answer:
12
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
x^2-3x-40 Factor
(x - 8) (x + 5)
The x intercepts are -5 and 8
(negative infinity, -5)
(8, positive infinity)