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Dmitry_Shevchenko [17]
3 years ago
6

How many solutions does the equation 3x-10(x+2)=13-7x

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

No solution

Step-by-step explanation:

1. Multiply the parenthesis by -10

2. Collect like terms

3. Cancel equal terms

4. You're left with -20=13, which is false. There is no solution.

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1 1/4 divided by 2/3
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Answer:

1.875

Step-by-step explanation:

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I think it’s (3,4) the third answer
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What quadrant is (6,-8) in
Oliga [24]

Answer:

quadrant 2

Step-by-step explanation:

because its a + and - and only quadrant 2 can have it

3 0
3 years ago
Jika garis 4x+ay = 8 dan ay=9x + 5 saling tegak lurus,maka nilai a
barxatty [35]

We are given equations as

4x+ay=8

Firstly, we will write in slope intercept form of line

y=mx+b

4x+ay=8

Subtract both sides by 4x

4x+ay-4x=-4x+8

ay=-4x+8

now, we can divide both sides by a

y=-\frac{4}{a} x+\frac{8}{a}

we can find slope

so, we get

m_1=-\frac{4}{a}

we are given second equation as

ay=9x+5

Firstly, we will write in slope intercept form of line

y=mx+b

divide both sides by a

y=\frac{9}{a} +\frac{5}{a}

we can find slope

m_2=\frac{9}{a}

we are given both lines are perpendicular

so, the multiplication of their slopes must  be -1

m_1\times m_2=-1

we can plug values

-\frac{4}{a}\times \frac{9}{a}=-1

now, we can solve for a

\frac{36}{a^2}=-1

Multiply both sides by a

\frac{36}{a^2}\times a^2=1\times a^2

36= a^2

now, we can solve for a

we get

a=-6,a=6...............Answer

4 0
3 years ago
In a jar of ten beads, seven are red and three are blue. a bead is drawn from the jar five times with replacement. what is the p
MatroZZZ [7]
<span>In a jar of ten beads; since 3 are blue; probability of picking a blue ball, B, = p(b) = 3/10. And P (of not picking a blue ball) ; p(b') = 7/10. Since it occurs with replacement, probabilities doesn't change Probaility of picking k blue balls from on n attempts is given by P_n(k) P_n(k) = (n, k) p^(k) q^(n -k) where p and q are b and b' respectively. P_5(2) = (5 , 2) (0.3)^(2) (0.7)^(5 - 2) P_5(2) = 5C2 (0.3)^(2) (0.7)^(3) = 0.3087</span>
6 0
3 years ago
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