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torisob [31]
3 years ago
6

Trigonometry heeellllppp plzzzz​

Mathematics
1 answer:
algol [13]3 years ago
3 0

Answer:

x ≈ 3.4 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin57° = \frac{opposite}{hypotenuse} = \frac{x}{4} ( multiply both sides by 4 )

4 × sin57° = x , thus

x ≈ 3.4 cm ( to 1 dec. place )

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Each of the 25 balls in a certain box is either red, blue or white and has a number from 1 to 10 painted on it. If one ball is t
Aneli [31]

Answer:

Not sufficient information

Step-by-step explanation:

Probability of white ball: P(W)

Probability of even number: P(E)

Probability of white ball or even number: P(W∨E) is asked

Considering case (1):

Probability of white ball and even number: P(W∧E) = 0

And we know that,

P(W∨E) = P(W) + P(E) - P(W∧E) = P(W) + P(E) - 0 = P(W) + P(E)

It is not sufficient to calculate the desired probability.

Considering case (2):

P(W) - P(E) = 0.2

Here, it is possible for P(W) and P(E) to get multiply values.

So P(W∨E) cannot be determined.

Considering cases (1) & (2):

P(W∧E) = 0 and P(W) - P(E) = 0.2

So, P(W∨E) = P(W) + P(E) = P(E) + 0.2 + P(E) = 2P(E) + 0.2

Again multiple answers are possible.

Such as, for P(E) = 0.4 (10 even balls) ⇒ P(W∨E) = 1

but for P(E) = 0.2 (5 even balls) ⇒ P(W∨E) = 0.6

So, the information are not sufficient.

3 0
3 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
2 years ago
Simplify: 3m over m-6 •5m3 - 30m2 over 5m2
vfiekz [6]
\frac{3(5m^{4}-2m +12)}{m-6} should be the right answer
3 0
2 years ago
7 x (-2) = ? * what’s the answer
Karolina [17]

Hey there!

<h3>Guide: </h3>
  • Negative & negative = positive
  • Positive & negative = negative
  • Positive & positive = positive
  • Negative & positive = negative

<h3>So, far <u>in your particular question we’re doing</u> <u>positive</u> (7) <u>&</u> <u>negative</u> (-2) so <u>that means your</u> <u>result will most likely be a negative </u></h3><h3 />

<em>Now let’s answer your question, shall we </em>

<h2>7 • (-2) =<em><u> -14</u></em> </h2>

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0
2 years ago
(a^3+14a^2+33a-20)\(a+4)
Oksi-84 [34.3K]
Perhaps you meant   <span>(a^3+14a^2+33a-20)   /   (a+4), for division by (a+4).  

Do you know synthetic division?  If so, that'd be a great way to accomplish this division.  Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.

Perform synth. div.  If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.

-4  /   1   14   33   -20
     ___    -4_-40    28___________
          1   10   -7       8

Here the remainder is not zero; it's 8.  However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
8 0
3 years ago
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