Question

BRAINLIEST ASAP! PLEASE HELP ME :)

Answer 1

Answer:

After 30.5430 ≅ 30.5 years the population will be same.

Step-by-step explanation:

Let, in (2010 + t) the population of these two species will be equal.

Hence, after t years of 2010, the population of species A will be $2000e^{0.05t}$ and the population of the species B will be $5000e^{0.02t}$.

As per our assumption, these population are same.

Hence,

$2000e^{0.05t} = 5000e^{0.02t}\\2e^{0.05t} = 5 e^{0.02t}\\e^{0.03t} = \frac{5}{2} \\0.03t = ln \frac{5}{2}\\t = 30.5430$.