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3 years ago

15

What is the interquartile range for the data set?

1 answer:

yarga [219]3 years ago

6 0

To solve this problem you must apply the proccedure shown below:

1- By definition, the formula for calculate the i<span>nterquartile range is

I</span><span>nterquartile range=Q3-Q1

Where Q1 is the lower quartile and Q3 is the upper quartile.

2-Keeping this on mind, you have:

</span>Interquartile range=Q3-Q1
<span>
Q3=245
Q1=201

</span>Interquartile range=245-201
Interquartile range=44
<span>
Therefore, the answer is: 44

</span>

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Find the value of x.

jok3333 [9.3K]

Answer:

Complementary

Step-by-step explanation:

5 0

3 years ago

Helpppp, what is a solution set for |a|=6<br><br> A<br> B<br> C<br> D

blondinia [14]

The answer should be a hope this helps :]

4 0

4 years ago

Determine the kinetic energy of 8000 Newton’s roller coaster car that is moving with a speed of 20.0 meters/seconds

ohaa [14]

Answer:

The kinetic energy of the roller coaster is 1600000 J.

Step-by-step explanation:

Given:

Mass of the roller coaster is 8000 Newton's and speed 20.0 meters/seconds.

Now, we need to find the kinetic energy $E_{k}$ of the roller coaster.

So, Mass of roller coaster (m) = 8000 N.

Velocity of roller coaster (v) = 20.0 m/s.

Now, putting the formula of kinetic energy:

$E_{k} = \frac{1}{2}\times m\times v^{2}$

$E_{k}=\frac{1}{2} \times 8000\times 20^{2}$

$E_{k}=\frac{1}{2} \times 8000\times 400$

$E_{k}=\frac{1}{2} \times 3200000$

$E_{k}=1600000$

Therefore, the kinetic energy of the roller coaster is 1600000 J.

3 0

4 years ago

In the following pair of polynomials, the second polynomial is a factor of the first. Factor completely x^3+3x^2-18x , x-4

OLga [1]

Answer:

The required factors are: x, (x + 6) and (x - 3).

Step-by-step explanation:

As per the question,

The given polynomial is:

$x^{3}+3x^{2}-18x$

Now,

BY factorization, we get

$x^{3}+3x^{2}-18x$

$=x(x^{2}+3x-18)$

By splitting the mid-term, that is split 3x like:

3x = 6x - 3x

Therefore,

$x(x^{2}+6x-3x-18)$

Now on further solving by taking common factor out, we get

$=x[x(x+6)-3(x+6)]$

$=x(x+6)(x-3)$

Therefore, the given second polynomial (x - 4), is not a factor of given polynomial $x^{3}+3x^{2}-18x$ .

Hence, the given polynomial has three factor x, (x + 6) and (x - 3).

8 0

4 years ago

What is the solution to -(6m+8)=4(17-m)

ale4655 [162]

<u>Answer:</u>

The solution to the problem is -38.

<u>Step-by-step explanation:</u>

-(6m + 8) = 4(17 - m)
=> -6m - 8 = 68 - 4m
=> -6m + 4m = 68 + 8
=> -2m = 76
=> m = 76/-2
=> m = -38

Hence, <u>the solution to the problem is -38.</u>

Hoped this helped.

$BrainiacUser1357$

5 0

3 years ago