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4 years ago

If the outlier is excluded, what happens to the mode

Mathematics

1 answer:

slega [8]4 years ago

6 0

Answer:

Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.

Is there any more details, I could give a better answer.

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PLEASE HELPPP!!!

Tems11 [23]

Answer:

a) $-16t^{2}+64t\geq40$

b) $[2-\frac{\sqrt{6}}{2} , 2+\frac{\sqrt{6}}{2}]$

(see attached picture for the number line)

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) $h_{max}=64ft$

d) t=2s

Step-by-step explanation:

Basically the ball will disappear when it is higher than 40 ft, so we can build the inequality like this:

$-16t^{2}+64t\geq40$

this is because the function represents it's height, so when the function is greater than or equal to 40, then the ball will disappear.

b) to solve the inequality, first we need to turn the ≥ symbol to an = symbol and solve for t, so we get:

$-16t^{2}+64t =40$

we can move the 40 to the other side of the equation so we get:

$-16t^{2}+64t-40=0$

we can factor the equation so it's easier to solve, so we get:

$-8(2t^{2}-8t+5) =0$

which simplifies to:

$2t^{2}-8t+5=0$

and we can use the quadratic formula to solve this equation, so we get:

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

so we get:

$t=\frac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(5)}}{2(2)}$

which yields:

$2\pm \frac{\sqrt{6}}{2}$

and next we need to test the posible intervals to see which one makes the inequality true, the possible intervals are:

$(-\infty, 2-\frac{\sqrt{6}}{2}]$ for a test value of 0

$[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}]$ for a test value of 1

$[2+\frac{\sqrt{6}}{2},\infty)$ for a test value of 4

so next we test each of the values in the original inequality and see if the inequality is true:

$(-\infty, 2-\frac{\sqrt{6}}{2}]$ for a test value of 0

$-16(0)^{2}+64(0)\geq40$

$0\geq40$ false

so this is not an answer.

$[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}]$ for a test value of 1

$-16(1)^{2}+64(1)\geq40$

$48\geq40$

true, so this is an answer.

$[2+\frac{\sqrt{6}}{2}, \infty)$ for a test value of 4

$-16(4)^{2}+64(4)\geq40$

$-16(16)+64(4)\geq40$

$-256+256\geq40$

$0\geq40$

false, so this is no answer.

So the answer is the interval:

$[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}]$

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) In order to find how high Penelope kick the football, we must find the vertex of the parabola which is gotten when graping the given function (see attached picture)

so we can use the following formula to find the t-value for this maximum height:

$t=-\frac{b}{2a}$

so we substitute the corresponding values:

$t=-\frac{64}{2(-16)}$

which yields:

t=2s

next, we can substitute this time into the original function to find the maximum height, so we get:

$h=-16(2)^{2}+64(2)$

which yields:

h=64 ft

d) We found the answer for d on the previous part where we got that t=2s

6 0

3 years ago

A survey was taken of students in math classes to find

Pie

I’m guessing you meant central tendency.

I’d say the mean is the best measure for period 2. This is because it doesn’t have any extremely low or high values which could distort the mean value.

If it did ie. 8, then I would choose median as it is less affected by anomalous results

6 0

3 years ago

your current wardrobe consists of eleven different items: three pairs of shoes, two pairs of pants, and six different shirts. yo

Alex73 [517]

A pair of shoes gives us 48 different outfits.

What is a linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included.
The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables." from Wolfram MathWorld: linear

We will employ the basic counting principle, which states that if one task can be completed in method A and another in way B, then both tasks may be completed in way A*B.

If mom buys 1 shirt, then total shirts(A) = 6+1 =7, total pants(B) = 2 and total shoes (C) = 3

By basic counting principle, number of outfits = A*B*C = 7*2*3 = 42 outfits possible

and

If mom buys 1 pair of shoes, then total shirts(A) = 6, total pants(B) = 2 and total shoes (C) = 3+1 = 4

By basic counting principle, number of outfits = A*B*C = 6*2*4 = 48 outfits possible

hence, buying a pair of shoes gives us 48 different outfits.

Learn more about linear equation

brainly.com/question/11897796

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6 0

2 years ago

Mary looks over reports on four of her workers. jack made 30 baskets in 5 hours. rudy made 32 baskets in 8 hours. sam made 40 ba

Elena L [17]

Well let's do some maths if each made a certain amount of baskets an hour you could divide them and figure out how many baskets were made per hour.
jack = 30/5 = 6 baskets per hour
Rudy = 32/8 = 4 baskets per hour
Sam = 40/12 =3.333 baskets per hour
Walter = 22/4 = 5.5 baskets per hour
according to this Jack had the greatest productivity

6 0

3 years ago

Sam owes 5 dollars to x friends and $3 to her sister. She owes $23 altogether.

sergey [27]

Answer:

Sam owes 4 friends $5

Step-by-step explanation:

We can set up the equation

23 = 5x + 3

Subtract the 3 from both sides

20 = 5x

x = 4 friends

7 0

3 years ago