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4 years ago

9

I need help to do this

1 answer:

nignag [31]4 years ago

4 0

So you would use the Y= mx+b format now we know m=2, so we input that into the eqhation. But there are still some missing values! So we use the coordinates (-1,-3) x = -1 and y= -3 we input those into the equation and solve for b, we find b = -1. Now that we have the b value we can write the equation: y = 2x -1

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The equations x minus y = 2, x minus 2 y = negative 2, x + y = 2, and x + 2 y = negative 2 are shown on the graph below. On a co

lbvjy [14]

Answer:

x - y = 2 and x + 2y = -2

Step-by-step explanation:

Since you have the graph, you can easily see that the point of interest is nearest the intersection of the <em>orange</em> and <em>pink</em> lines.

__

Recognizing that the intercepts of a line in standard form are ...

ax +by =c

x-intercept: c/a

y-intercept: c/b

You can easily determine the corresponding intercepts for the given lines. We can tell from the graph that we only need to know what the y-intercept is in order to match the equation to the line. Here are the y-intercepts:

x -y = 2 ⇒ (0, -2) — orange
x -2y = -2 ⇒ (0, 1) — blue
x +y = 2 ⇒ (0, 2) — green
x +2y = -2 ⇒ (0, -1) — pink

The system of equations with the desired solution is ...

x -y = 2 and x +2y = -2

6 0

3 years ago

Read 2 more answers

The coordinates of the points bellow represent the vertices of a rectangle: P: (2,2). Q:(6,2) R:(6,5) S:(2,5) What is the perime

skad [1K]

Answer:

Therefore the value of perimeter of the rectangle is 14 in.

Step-by-step explanation:

The opposite sides of a rectangle are congruent.

The perimeter of a rectangle is 2(length + width)

The area of a rectangle is (length×width).

Given the vertices of a rectangle are P(2,2), Q(6,2), R(6,5) and S(2,5).

To find the the perimeter, first we need the sides of the rectangle.

The distance between two points(x₁,y₁) and (x₂,y₂) is

$=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between P and Q is

$=\sqrt{(6-2)^2+(2-2)^2}$ in

$=\sqrt {4^2+0^2}$ in

=4 in

The distance between Q and R is

$=\sqrt{(6-6)^2+(5-2)^2$ in

$=\sqrt{0^2+3^2}$ in

=3 in

The distance between R and S is

$=\sqrt{(2-6)^2+(5-5)^2}$ in

$=\sqrt{ (-4)^2}$ in

=4 in

The distance between S and P is

$=\sqrt{(2-2)^2+(2-5)^2}$ in

$=\sqrt{(-3)^2}$ in

=3 in

Therefore the length of the rectangle is = 4 in.

an the width of the rectangle is = 3 in

Therefore the perimeter of the rectangle is =2(4+3) in

=14 in

7 0

3 years ago

Can someone please help me

zhuklara [117]

So what is the question?

7 0

3 years ago

OLga [1]

Answer:

a) 3x²-4x-15

b) binomial

5 0

3 years ago

Easy question practically free points

Scilla [17]

The answer is 6x+12. Have a GREAT day!!!! :)

5 0

3 years ago

Read 2 more answers