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harina [27]
3 years ago
12

The equations x minus y = 2, x minus 2 y = negative 2, x + y = 2, and x + 2 y = negative 2 are shown on the graph below. On a co

ordinate plane, there are 4 lines. Green line goes through (0, 2) and (2, 0). Orange line goes through (2, 0) and (0, negative 2). Pink line goes through (2, negative 2), and (0, negative 2). Blue line goes through (0, negative 2) and (2, 2). Which system of equations has a solution of approximately (0.7, –1.4)? x minus y = 2 and x + 2 y = negative 2 x minus 2 y = negative 2 and x + y = 2 x minus y = 2 and x minus 2 y = negative 2 x + y = 2 and x + 2 y = negative 2

Mathematics
2 answers:
lbvjy [14]3 years ago
6 0

Answer:

  x - y = 2   and   x + 2y = -2

Step-by-step explanation:

Since you have the graph, you can easily see that the point of interest is nearest the intersection of the <em>orange</em> and <em>pink</em> lines.

__

Recognizing that the intercepts of a line in standard form are ...

  ax +by =c

  x-intercept: c/a

  y-intercept: c/b

You can easily determine the corresponding intercepts for the given lines. We can tell from the graph that we only need to know what the y-intercept is in order to match the equation to the line. Here are the y-intercepts:

  • x -y = 2   ⇒   (0, -2) — orange
  • x -2y = -2   ⇒   (0, 1) — blue
  • x +y = 2   ⇒   (0, 2) — green
  • x +2y = -2   ⇒   (0, -1) — pink

The system of equations with the desired solution is ...

  x -y = 2  and  x +2y = -2

Novosadov [1.4K]3 years ago
3 0

Answer:

A: x-y= 2 and x+2y= -2

Step-by-step explanation:

I got it right on Edge 2020

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