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AlladinOne [14]
3 years ago
10

(¬‿¬) Find the number of real number solutions for the equation. x^2+9x+20=0

Mathematics
1 answer:
mart [117]3 years ago
8 0

To find the nature of solutions of a quadratic equation we can find the discriminant.

The standard form of a quadratic equation is ax² + bx + c = 0.

Formula to find the discriminant = b² - 4ac.

So, first step is to compare the given equation with the above equation to get the value of a, b, and c.

After comparing the two equations we will get a =1, b = 9 and c = 20.

Next step is to plug in these value in the formula of discriminant. So,

Discriminant = 9² - 4(1)(20)

= 81 - 80

= 1

Since 1 is a positive perfect square number.

So, we will get two real solutions for this equation.

Hence, the correct choice is C.

Hope this helps you.

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Answer:

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Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
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Answer:  (C) shifts 6 units to the LEFT

<u>Step-by-step explanation:</u>

The vertex form of an absolute value equation is:

y = a |x - h| + k    where;

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Since h represents the x-coordinate and the x-axis is left to right, then h shifts  the graph left or right.

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x + 6 is actually x - (-6), so h is negative and the graph shifts to the left.

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