Question

(¬‿¬) Find the number of real number solutions for the equation. x^2+9x+20=0

Answer 1

To find the nature of solutions of a quadratic equation we can find the discriminant.

The standard form of a quadratic equation is ax² + bx + c = 0.

Formula to find the discriminant = b² - 4ac.

So, first step is to compare the given equation with the above equation to get the value of a, b, and c.

After comparing the two equations we will get a =1, b = 9 and c = 20.

Next step is to plug in these value in the formula of discriminant. So,

Discriminant = 9² - 4(1)(20)

= 81 - 80

= 1

Since 1 is a positive perfect square number.

So, we will get two real solutions for this equation.

Hence, the correct choice is C.

Hope this helps you.