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Andreas93 [3]
3 years ago
9

Given: AM = 8, AB = 5x +1 and M is the midpoint of AB, find x and AB X= AB=

Mathematics
1 answer:
NARA [144]3 years ago
3 0

Answer:

x = 3

AB = 16

Step-by-step explanation:

Given: AM = 8, AB = 5x +1 and M is the midpoint of AB, the AM = MB

AB = 2AM

5x+1 = 2(8)

5x + 1 = 16

x = 16 - 1

5x = 15

x = 15/5

x = 3

Hence the value of x is 3

Since AB = 5x+1

AB = 5(3) + 1

AB = 15 + 1

AB = 16

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Quadratic Functions Helppp please!!! questions attached below
OleMash [197]

Answer:

Q 30) x = -3 or x = 12.

Q 31) x = 1 or x = 2.

Q 32) x = -1/2 or x = 8.

Q 33) x = 2/5 or x = 3.

Q 34) x = 1.80424764151 or x = -0.5542476415.

Q 35) x = 1.5 or x = -1/3.

Step-by-step explanation:

Q 30)

x^2 - 9x - 36 = 0.

Solving by factoring:

Multiplying 1 and 36 yields 36. The factors whose difference results in 9 are 12 and 3. Therefore:

x^2 - 12x + 3x - 36 = 0.

x(x - 12) + 3(x - 12) = 0.

(x + 3)(x - 12) = 0.

Either x + 3 = 0 or x - 12 = 0.

Therefore, x = -3 or x = 12.

Q 31)

x^2 - 3x + 2 = 0.

Solving by factoring:

Multiplying 1 and 2 yields 2. The factors whose sum results in 3 are 2 and 1. Therefore:

x^2 - 2x - x + 2 = 0.

x(x - 2) - 1(x - 2) = 0.

(x - 1)(x - 2) = 0.

Either x - 1 = 0 or x - 2 = 0.

Therefore, x = 1 or x = 2.

Q 32)

2x^2 - 15x - 8 = 0.

Solving by factoring:

Multiplying 2 and 8 yields 16. The factors whose difference results in 15 are 16 and 1. Therefore:

2x^2 - 16x + x - 8 = 0.

2x(x - 8) + 1(x - 8) = 0.

(2x + 1)(x - 8) = 0.

Either 2x + 1 = 0 or x - 8 = 0.

Therefore, x = -1/2 or x = 8.

Q 33)

5x^2 - 17x + 6 = 0.

Solving by factoring:

Multiplying 5 and 6 yields 30. The factors whose sum results in 17 are 15 and 2. Therefore:

5x^2 - 15x - 2x + 6 = 0.

5x(x - 3) - 2(x - 3) = 0.

(5x - 2)(x - 3) = 0.

Either 5x - 2 = 0 or x - 3 = 0.

Therefore, x = 2/5 or x = 3.

Q 34)

4x^2 - 5x - 4 = 0.

Solving by completing the square:

4x^2 - 5x = 4.

x^2 - 5x/4 = 1.

(x)^2 - 2*(x)*(5/8) + (5/8)^2 = 1 + (5/8)^2.

(x - 5/8)^2 = 1 + 25/64.

(x - 5/8)^2 = 89/64.

x - 5/8 = ±1.17924764151.

x - 5/8 = 1.17924764151 or x - 5/8 = -1.17924764151.

Therefore, x = 1.80424764151 or x = -0.5542476415.

Q 35)

6x^2 - 7x - 3 = 0.

Solving by quadratic formula:

x = (-b ± √(b^2 - 4ac))/2a.

a = 6, b = -7, and c = -3.

x = (-(-7) ± √((-7)^2 - 4*(6)*(-3)))/2(6).

x = (7 ± √(49 + 72))/12.

x = (7 ± √(121))/12.

x = (7 ± 11)/12.

x = (7 + 11)/12 or x = (7 - 11)/12.

x = 18/12 or x = -4/12.

Therefore, x = 1.5 or x = -1/3.

In summary:

Q 30) x = -3 or x = 12!!!

Q 31) x = 1 or x = 2!!!

Q 32) x = -1/2 or x = 8!!!

Q 33) x = 2/5 or x = 3!!!

Q 34) x = 1.80424764151 or x = -0.5542476415!!!

Q 35) x = 1.5 or x = -1/3!!!

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Answer:

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Step-by-step explanation:

The pairs of angles referenced in statements 1 and 2 are "corresponding" angles, so the Corresponding Angle Postulate applies.

The Reflexive Property is what says something is the same as itself. This is used in statement 3.

The upshot of the AA Similarity postulate is to say triangles are similar (as in statement 4).

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kaheart [24]

Answer:

\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

Step-by-step explanation:

First, simplify each term:

\sin\left(\dfrac{\pi}{2}+\alpha\right)=\cos \alpha\\ \\\cos \left(\dfrac{\pi}{2}+\alpha\right)=-\sin \alpha\\ \\\cos \left(\alpha-\dfrac{3\pi}{2}\right)=-\sin \alpha\\ \\\sin \left(\dfrac{3\pi}{2}+\alpha\right)=-\cos \alpha

Then given expression is equivalent to

\cos ^3\alpha+(-\sin \alpha)^3-(-\sin \alpha)+(-\cos \alpha)\\ \\=\cos ^3\alpha-\sin^3 \alpha+\sin \alpha-\cos \alpha\\ \\=(\cos\alpha-\sin\alpha)(\cos^2\alpha+\cos\alpha\sin\alpha+\sin^2\alpha)-(\cos\alpha-\sin\alpha)\\ \\=(\cos\alpha-\sin\alpha)(1+\cos\alpha\sin\alpha-1)\ \ [\cos^2\alpha+\sin^2\alpha=1]\\ \\=\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

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3 years ago
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