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butalik [34]
4 years ago
5

How does using zero pairs help you solve equations?

Mathematics
1 answer:
Alik [6]4 years ago
8 0

Answer:

Just do

Step-by-step explanation:

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Which quadratic function is represented by the graph?
KatRina [158]

Answer:

where are the multiple choice

Step-by-step explanation:

3 0
3 years ago
The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th
vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by P(t)=1.394(1.006)^t

To find the derivative you need to:

\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t

To find the population growing at the start of 2014 we say t = 0

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year

To find the population growing at the start of 2015 we say t = 1

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year

To convert billion to million you multiple by 1000

P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year

6 0
3 years ago
Kyle is making 9 birdhouses. He uses 8 nails for each birdhouse. If Kyle has a box of 100 nails, how many nails will he have lef
iragen [17]
9 x 8 = 72 
100 - 72 =28

Hope this helps
7 0
3 years ago
What is the probability of rolling an even number on a standard number cube and then rolling a one
expeople1 [14]

Answer:

multiply the chances

1/2 (every other number is even right)

1/2 x 1/6 (if it is a normal dice) = 1/12

1/12 chance

Step-by-step explanation:

4 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
fenix001 [56]

Answer:

x^6y^3

Step-by-step explanation:

<u>Given polynomial:</u>

  • 8x^6y^5 - 3x^8y^3

<u>Get prime factors:</u>

  • 2*2*2*x*x*x*x*x*x*y*y*y*y*y - 3*x*x*x*x*x*x*x*x*y*y*y

<u>Common factors of the two terms:</u>

  • x*x*x*x*x*x*y*y*y = x^6y^3

<u>So</u>

  • x^6y^3(8y^2 - 3x^2)

x^6y^3 is the GCF of this polynomial

4 0
3 years ago
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