How does using zero pairs help you solve equations?

Debora [2.8K]

Part 1: getting the area of the entrance
The entrance has a trapezoid shape.
Area of trapezoid can be calculated using the following rule:
Area of trapezoid = average base * height
The aveage base = (b1+b2)/2 = (8+16)/2 = 12 ft
height of trapezoid = 4 ft
Therefore:
area of entrance = 12*4 = 48 ft^2

Part 2: getting the area of the house:
area of house = area of back porch + area of side deck + area of play room + area of entrance
i- getting the area of the back porch:
The back porch is a square with side length = 6 ft
Therefore:
area of back porch = 6*6 = 36 ft^2
ii- getting the area of side deck:
The side deck is a rectangle whose length is 14 ft and width is 3 ft
Therefore:
area of side deck = 14*3 = 42 ft^2
iii- getting the area of play room:
The play room is a rectangle whose length is 14 ft and width is 16 ft
Therefore:
area of play room = 14*16 = 224 ft^2
iv- area of entrance is calculated in part 1 = 48 ft^2
Based on the above:
area of house = 36 + 42 + 224 + 48 = 350 ft^2

hope this helps :)

5 0

3 years ago

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are x number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of x as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

4 0

3 years ago

Rob can mop a warehouse in 10 hours. Maria can mop the same warehouse in 11 hours. Find how long it would take them if they work

Natali [406]

The answer would be 21 good luck hope you get it correct

4 0

3 years ago

Read 2 more answers

Do you add or multiple?

BaLLatris [955]

Add your welcome I think

3 0

3 years ago

A falling object travels a distance given by the formula d=3t+5t2, where d is measured in feet and t is measured in seconds. How

Romashka-Z-Leto [24]

Answer:

4.52secs

Step-by-step explanation:

Given the height of a falling object expressed as;

d=3t+5t^2

If the object travel 84 feet, we are to find the time t it takes to travel. On substituting;

84 = 3t+5t^2

3t+5t^2 - 84 = 0

t = -5±√25-4(3)(-84)/2(3)

t = -5±√25+1008/6

t = -5±32.14/6

t = -5+32.14/6

t = 27.14/6

t = 4.52 secs

Hence it will take 4.52secs for the object to travel 84feet

8 0

3 years ago