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max2010maxim [7]
3 years ago
8

Suppose that 11 inches of wire costs 44cents.

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

we can bought 6 inches of wire which costs 24 cents

maksim [4K]3 years ago
4 0
6 inches of wire can be bought with 24 cents.

44/11 = 4
4 cents per inch
24/4 = 6
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A. 1/5<br><br> B. 1/3<br><br> C. 7/15<br><br> D. 1/2
Allisa [31]

P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\ |\Omega|=15\cdot14=210\\ |A|=3\cdot14=42\\ |A \cap B|=3\cdot7=21\\\\ P(A)=\dfrac{42}{210}=\dfrac{7}{35}\\ P(A \cap B)=\dfrac{21}{210}=\dfrac{1}{10}\\\\ P(B|A)=\dfrac{\dfrac{1}{10}}{\dfrac{7}{35}}=\dfrac{1}{10}\cdot\dfrac{35}{7}=\dfrac{1}{2}\Rightarrow \text{D}

4 0
4 years ago
Jeffrey says he has 6.8 dollars. How do you write the decimal 6.8 when it refers to money? Explain
katen-ka-za [31]

Answer:

$6.80, dollar and cent amounts are always written to two decimal places.

7 0
4 years ago
Which set represents a pythagorean triple
AnnyKZ [126]

Answer:

30, 40, 50 which is choice C

Step-by-step explanation:

Square the smaller two values (30 and 40)

30^2 = 900

40^2 = 1600

then add those results

900+1600 = 2500

Notice how 50^2 = 2500 as well. This shows us that 30^2 + 40^2 = 50^2 is a true equation. Both sides lead to the same result 2500. Therefore, a triangle with sides 30, 40, 50 is a right triangle. This is based on the 3-4-5 pythagorean triple, just each side has been multiplied by 10.

5 0
3 years ago
Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).
ad-work [718]
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0
3 years ago
Find all real and non-real roots of the function ƒ(x) = x2 + 49. Question 1 options: A) x = –7, 7 B) x = –7i, 7i C) x = –49i, 49
malfutka [58]

Given:

The function is:

f(x)=x^2+49

To find:

The all the real and non-real roots of the given function.

Solution:

We have,

f(x)=x^2+49

For roots, f(x)=0,

x^2+49=0

x^2=-49

Taking square root on both sides, we get

x=\pm \sqrt{-49}

x=\pm \sqrt{-1}\sqrt{49}

x=\pm 7i                [\because \sqrt{-1}=i]

The roots of the given function are -7i and 7i.

Therefore, the correct option is B.

6 0
3 years ago
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