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max2010maxim [7]
3 years ago
8

Suppose that 11 inches of wire costs 44cents.

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

we can bought 6 inches of wire which costs 24 cents

maksim [4K]3 years ago
4 0
6 inches of wire can be bought with 24 cents.

44/11 = 4
4 cents per inch
24/4 = 6
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25% of what number is 20
ycow [4]

Answer:

100

Step-by-step explanation:

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If you randomly choose a number below
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There are 8 total numbers. Of those 8 numbers, 6 are odd. So, the probability of picking an odd number is 6/8 = 3/4 = 0.75.

Hope this helps!! :)

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Please solve question 6, doing surds
Amiraneli [1.4K]

See the attached diagram, it has all the information you need.

(a) If the green radii are all 1, then the orange diameters are all 2 + √2, so that the orange radii are (2 + √2)/2 = 1 + √2/2.

This is because we can join the radii of two adjacent green circles to form the sides of a square with side length equal to twice the radius - i.e. the diameter - of the green circles. The diagonal of any square occurs in a ratio to the side length of √2 to 1. Then we get the diameter of an orange circle by summing this diagonal length and two green radii, and hence the radius by dividing this by 2.

(b) We get the blue diameter in the same way. It has length (2 + √2) (1 + √2/2) = 3 + 2√2, so that the blue radius is (3 + 2√2)/2 = 3/2 + √2.

7 0
3 years ago
The probability of a randomly selected adult in one country being infected with a certain virus is 0.005. In tests for the​ viru
myrzilka [38]

Answer:

The probability is 12.66%.

This is a low probability, so it is unlikely for such a combined sample to test positive.

Step-by-step explanation:

If the probability of being infected is 0.005, the probability of not being infected is 0.995.

Then, to find the probability of at least one of the 27 people being infected P(A), we can find the complementary case: all people are not infected: P(A').

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Then we can find P(A) using:

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P(A) = 0.1266 = 12.66\%

This is a low probability, so it is unlikely for such a combined sample to test positive.

6 0
3 years ago
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