Question

Which is a solution to (x - 2)(x + 10) = 13 ?

Answer 1

Answer:

2 and -10.

Step-by-step explanation:

(x-2)(x+10)=13

$x^{2} +10x-2x-20 =13$

$x^{2} +8x-20 =13$

$x1=\frac{-8+\sqrt[2]{64-4(-20)} }{2}$

$x1=\frac{-8+\sqrt[2]{64+80} }{2}$

$x1=\frac{-8+12 }{2}$

$x1=2.$

$x2=\frac{-8-\sqrt[2]{64-4(-20)} }{2}$

$x2=\frac{-8-\sqrt[2]{64+80} }{2}$

$x2=\frac{-8-12 }{2}$

$x2=-10.$

Answer 2

The answer is:
x=3,-11