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3 years ago

What is the volume and the surface area of the storage chest

Mathematics

1 answer:

Anarel [89]3 years ago

8 0

Answer:

idk the answer but i know this hope is helpful

Step-by-step explanation:

The volume, or amount of space inside a box is h × W × L. The outside surface area of a box is 2(h × W) + 2(h × L) + 2(W × L)

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The slope of the line whose equation is 3y + 2x = 1 is: A.)-2/3 B.)-3/2 C.)1/3

mojhsa [17]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3y + 2x = 1 into this form

Subtract 2x from both sides

3y = - 2x + 1 ( divide all terms by 3 )

y = - $\frac{2}{3}$ x + $\frac{1}{3}$ ← in slope- intercept form

with slope m = - $\frac{2}{3}$ → A

4 0

2 years ago

For triangle ABC, angle A=110, angle B=43, and side b=15. Find side c.

vredina [299]

Answer: 10

<u>Step-by-step explanation:</u>

First, find m∠C by using the Triangle Sum Theorem:

∠A + ∠B + ∠C = 180°

110 + 43 + ∠C = 180°

153 + ∠C = 180°

∠C = 27°

Next, Use the Law of Sines to solve for c:

$\dfrac{b}{sin\ B}= \dfrac{c}{sin\ C}$

$\dfrac{15}{sin\ 43}= \dfrac{c}{sin\ 27}$

$\dfrac{15\ sin\ 27}{sin\ 43}= c$

$10 = c$

8 0

3 years ago

Find the volume of the solid generated when R (shaded region) is revolved about the given line. x=6−3sec y, x=6, y= π 3, and

Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$

where:

$r=6-(6-3 sec(y))$

$r=3 sec(y)$

a=0

$b=\frac{\pi}{3}$

so the volume becomes:

$V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy$

This can be simplified to:

$V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy$

and the integral can be rewritten like this:

$V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy$

which is a standard integral so we solve it to:

$V=9\pi[tan y]\limits^\frac{\pi}{3}_0$

so we get:

$V=9\pi[tan \frac{\pi}{3} - tan 0]$

which yields:

$V=9\pi\sqrt{3}$ ]

6 0

3 years ago

For the function below, give the ordered pair if x = 2 f(x)=-3(x+2)2+9

Kay [80]

Answer:

(2, -39)

Step-by-step explanation:

f(x)=-3(x+2)^2+9

f(2)=-3(2+2)^2+9

f(2)=-3(4)^2+9

f(2)=-3(4)(4)+9

f(2)=-3(16)+9

f(2)=-48+9

f(2)=-39

8 0

2 years ago

HELPPP ME PLS!!!!!!!!!!!!

mestny [16]

The correct answer is 1/3

7 0

2 years ago

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