Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
There are no solutions
Step-by-step explanation:
Because the lines are parallel, they will never meet, meaning there are no solutions to this system of equations
I don’t know the rest, but I think the 1st and 3rd ones are true! I hope this helps some, I’m sorry if it’s incorrect!
Answer:
The answer is D
Step-by-step explanation:
Coplanar means that they are on the same closed area(or plane)- P, M, C, N are all on the same Plane.
