6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
Answer:
5.25 and for the second part 126
Step-by-step explanation:
trust
Answer:
Step-by-step explanation:
-1/2 + (3/4 x 4/9)
-1/2 + (3/9)
= - 1/2 + (1/3)
= - 1/6
Since this is an obtuse triangle, Point O is not equidistant from A, B, and C. Point O is not on the perpendicular bisectors, so the third statement is true. Point O is equidistant from AB, BC, and CA because these lines are pressed against the circpe in a mannered way.
Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
