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dezoksy [38]
3 years ago
14

Total employment for sheet metal workers in 2016 is projected to be 201,000. If this is a 6.3% increase from 2006, approximately

what was the total employment in 2006?
a.
214,000
b.
188,000
c.
195,000
d.
189,000
Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer:

d.189000

Step-by-step explanation:

We are given that total employment for sheet metal workers in 2016 is projected to be 201,000.

If this is 6.3% increase from 2006

We have to find the total number of employment in 2006

In 2016, Total number of employments =201,000

Let x be the total number of employments in 2006

Then 6.3% x+x=201,000

\frac{63}{1000}x+x=201000

\frac{63x+1000x}{1000}=201000

\frac{1063}{1000}x=201000

x=\frac{201000\times 1000}{1063}

x=189087.4

x=189087

Hence, total number of employments in 2006=189000 approximately.

Option d is true.

natka813 [3]3 years ago
7 0
201,000 = (2006 employment) +6.3%*(2006 employment)

201,000 = (2006 employment)*(1.063)

201,000/1.063 = (2006 employment) ≈ 189,087 . . . . . matching selection D
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