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4 years ago

What is the midpoint of (-1,5) (5,5)

Mathematics

2 answers:

nevsk [136]4 years ago

7 0

To find the midpoint, add the two X values and divide by 2 and add the two Y values and divide by 2.

-1 + 5 = 4/2 = 2

5 +5 = 10 /2 = 5

Midpoint = (2,5)

AlexFokin [52]4 years ago

5 0

Answer:

(2,5)

Step-by-step explanation:

The points are on the same y, which is 5, so we only have to find the distance between the x values.

Distance formula = $M = \frac{x_{1} + x_{2} }{2}$

$M = \frac{-1 + 5}{2}$

Mid = \frac{4}{2} [tex]

Mid = 2

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An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago

Slope is 3/7,and (4,9) is on the line

TiliK225 [7]

Answer:

$y-9=\frac{3}{7}(x-4)$

$y=\frac{3}{7}x+\frac{51}{7}$

Step-by-step explanation:

To write the equation of the line using a slope and a point, use the point-slope formula $y-y_1 = m(x-x_1)$ . Here m is 3/7. And the point $(x_1,y_1)$ is (4,9). Substitute the values and simplify.

$y-y_1=m(x-x_1)\\y-9=\frac{3}{7}(x-4)\\y-9=\frac{3}{7}x - \frac{12}{7}\\y=\frac{3}{7}x -\frac{12}{7} + 9\\y=\frac{3}{7}x + \frac{51}{7}$

Both the point slope form and the final simplified form are considered equations of the line.

3 0

3 years ago

Victoria is interested in opening her own candy store. She has researched and found that of the 14 stores she investigated, the

Anna71 [15]

Answer:

99% confidence interval for the average start up cost is [76.575 , 123.425].

Step-by-step explanation:

We are given that of the 14 stores Victoria investigated, the average start up cost is 100 thousand dollars with a standard deviation of 29.1 thousand dollars.

So, the pivotal quantity for 99% confidence interval for the population average start up cost is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average start up cost = 100 thousand dollars

$\sigma$ = sample standard deviation = 29.1 thousand dollars

n = sample of stores = 14

$\mu$ = population average start up cost

So, 99% confidence interval for the average start up cost, $\mu$ is ;

P(-3.012 < $t_1_3$ < 3.012) = 0.99

P(-3.012 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 3.012) = 0.99

P( $-3.012 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $3.012 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

P( $\bar X-3.012 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +3.012 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-3.012 \times {\frac{s}{\sqrt{n} }$ , $\bar X +3.012 \times {\frac{s}{\sqrt{n} }$ ]

= [ $100-3.012 \times {\frac{29.1}{\sqrt{14} }$ , $100+3.012 \times {\frac{29.1}{\sqrt{14} }$ ]

= [76.575 , 123.425]

Therefore, 99% confidence interval for the population average start up cost for a candy store is [76.575 , 123.425].

8 0

3 years ago

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Phantasy [73]

Answer:

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Step-by-step explanation:

Just try to visualize it. If a function is reflected across the x-axis, that means that positive values are flipped and become negative and negative values become positive.

So, g(x)=-f(x).

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3 years ago

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harkovskaia [24]

Answer:160

Step-by-step explanation:

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3 years ago

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