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2 years ago

12

Are the two triangles below similar?PLEASE HELP ME!!!!!!!!!!

2 answers:

dimulka [17.4K]2 years ago

5 0

Answer:

im going with number 3 sorry if im wrong

Step-by-step explanation:

laiz [17]2 years ago

5 0

Answer:

Yes; they have congruent corresponding angles.

Step-by-step explanation:

The two triangles are similar because their angles measure are the same. This is because 70 + 28 + 92 = 180 degrees and all Euclidean triangles angles measures must have a sum of exactly 180 degrees.

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Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.

melomori [17]

V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C
</span>

4 0

3 years ago

What is the answer for 3r+8=2r+12

Marina86 [1]

Answer:

r=4

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago

If you flip three fair coins, what is the probability that you’ll get all three heads?

Sladkaya [172]

Answer:

3/6

Step-by-step explanation:

no idea if its right

5 0

3 years ago

Record this number in standard form: twenty-five thousand, four hundred fifty

bogdanovich [222]

Hi!

25 thousand

4 hundred

50

<h3>25,000 + 400 + 50 = 25,450</h3><h2>The answer is 25,450</h2>

Hope this helped you! :)

-Peredhel

4 0

3 years ago