Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Dear User,
Answer to your query is provided below
The time will be 8am on Wednesday when flight arrive in Tokyo.
Step-by-step explanation:
Here, You can see that when 11 a.m. in Johannesburg, it is 6 p.m. the same day in Tokyo, Japan ; this means 7Hrs. gap.
Further, A flight leaves Johannesburg at 6 a.m. on Tuesday for Tokyo takes 18 hours in the air, with an additional 1 hour stop-over on land.
So, 6a.m. + 18hr.+1hr.+7hr. = 8am on Wednesday in Tokyo (Arrival)
Answer:
39 X 10=75
Step-by-step explanation:
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To find the area you do base times height. Base is the number across,and height is the number that is up and down.So in this case you will multiply 9 and 5 and 9 and 7 and get 45 and 72.Then you will add 45 and 72 together and get 117. So the area is 117. Answer 117. Hope this helps :D.
I pretty sure it’s a linear function
