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3 years ago

Write As Percent

1 answer:

5 0

To make a fraction a percent, you have to divide the numerator by the denominator. You get a decimal. Multiply the decimal by 100 to get the percent or just move the decimal two places to the right.

So,

Divide 1 by 5 and you get 0.20

Multiply 0.20 by 100. The answer is 20%

Divide 2 by 3 and you get 0.6666.......

Multiply 0.6666..... by 100 and you get 66.6%

Divide 1 by 40 and you get 0.025.

Multiply 0.025 by 100 and you get 2.5%

Divide 4 by 8 and you get 0.5.

Divide 0.5 by 100 and you get 50%.

Divide 12/16 and you get 0.75.

Multiply 0.75 by 100 and you get 75%.

<em>Hope it helps</em>

You might be interested in

The mean salary of people living in a certain city is $37500 with a standard deviation of $1561. a sample of 33 people is select

Murrr4er [49]

The probability is 0.9671.

The z-score for this is given by

z = (x - μ)/(σ/√n)
z = (38000-37500)/(1561/(√33)) = 1.84.

Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, this is 0.9671.

8 0

3 years ago

Area can be defined as the number of square units it takes to cover the inside

Anni [7]

Answer:

Step-by-step explanation:

It is making me add 20 characters to my answer so ignore this :)

5 0

3 years ago

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago

Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation

mash [69]

Answer:

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

5 0

3 years ago

Identify the pattern and find the next number in the pattern. 0.8, 3.2 12.851.2

Savatey [412]

For this case we have the following sequence:
0.8
3.2
12.8
51.2
This sequence can be written as:
0.8 = 0.2 * 4 = 0.2 * 4 ^ 1
3.2 = 0.2 * 16 = 0.2 * 4 ^ 2
12.8 = 0.2 * 64 = 0.2 * 4 ^ 3
51.2 = 0.2 * 256 = 0.2 * 4 ^ 4
Therefore, we have that the generic expression for this case is:
an = 0.2 * 4 ^ n
Then, the next number is then:
a5 = 0.2 * 4 ^ 5 = 0.2 * 1024 = 204.8
answer
the next number in the pattern is 204.8

8 0

3 years ago