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Pie
3 years ago
7

Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation

? A) x + 3 B) x − 1 C) x − 4 D) x − 3
Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

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Hope I helped!

Giving me brainliest is much appreciated! :).

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3 years ago
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Vera_Pavlovna [14]

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6 0
3 years ago
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Yuliya22 [10]

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7 0
2 years ago
Answer of a ²-10a+16-6b-b^2​
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\quad a^2-10a+16-6b-b^2

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

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5 0
3 years ago
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6 0
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Read 2 more answers
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