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nasty-shy [4]
3 years ago
14

while exercising cody traveled 4 2/7 kilometers. if he walked 2 3/9 kilometers and jogged the rest, how many kilometers did he j

og​

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0

Answer:

Step-by-step explanation:

irina [24]3 years ago
5 0

Answer:

41/21km or 1 20/21km

Step-by-step explanation:

1) simplify fractions: 4 2/7 = 30/7 and 2 3/9 = 7/3

2) find common denominator: 90/21 - 49/21

3) subtract: 41/21

4) simplify: 41/21 or 1 20/21

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Sphinxa [80]
??? Im lost in this question, could you be more specific?
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If a= 3+√5/2 then find the value of a square+1/a square
kondor19780726 [428]
This will help u i hooe

8 0
4 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
4 years ago
What is the interest on a loan of $200 if you borrow it for 24 months at a yearly interest rate of 9%?
kkurt [141]

Answer:

$36

Step-by-step explanation:

I = Prt

P = 200

r = 0.09

t = 24/12 = 2

I = 200 x 0.09 x 2

I = 36

6 0
3 years ago
List all the factors of 8 from least to greatest for my brother
sesenic [268]

Answer:

1,2,4,8

Step-by-step explanation:

8/1=8

8/2=4

8/4=2

4 0
3 years ago
Read 2 more answers
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