We want to compare averages. From the histogram we have we don't know the exact mean, but if we just assume the average in each bin is the midpoint of the bin we can make an estimate.
Supplier A has
mean = ( 22(64) + 27(66) + 26(68) + 15(70) + 10(72) )/(22+27+26+15+10)
mean = 6728/100 = 67.28 grams
Supplier B has mean 66.5
Answer: Choose Supplier A
(work shown above)
<h2><u>
Answer:</u></h2>
7m^2 - 11m - 2
<h2><u>
Step-by-step explanation:</u></h2>
Distribute the negative.
4m^2 - m + 2 + 3m^2 - 10m - 4 = ?
Now, add the like terms.
4m^2 + 3m^2 = 7m^2
-m + (-10m) = -11m
2 + (-4) = -2
7m^2 - 11m - 2
Answer:
Below in bold.
Step-by-step explanation:
x can have any real value - the domain is (-∞, ∞).
f(x) cannot be 0 or negative, no matter how negative x is, - the range is (0, ∞)
A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
