Answer:
56 and there will be 1 foot of ribbon left over
Step-by-step explanation:
225/4=56.25
I got -2,2....................
Answer:
The ratio of the surface areas and volume is 8((5y+5x) /25xy)
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes.
Let us assume that the radius =x
Radius r=5x/4
And the height =y
Height h= 5y/4
We know that the total surface area of a cylinder is
A total = 2πrh+2πr²
We can factor out 2πr
A total = 2πr(h+r)
The volume of a cylinder is given as
v= πr²h
The surface area and volume ratios
Can be expressed as
2πr(h+r)/πr²h= 2(h+r)/rh
= (2h+2r)/rh= 2h/rh + 2r/rh
= 2/r + 2/h
= 2(1/r + 1/h)
Substituting our value of x and y
For radius and height we have
= 2(1/5x/4 + 1/5y/4)
=2(4/5x + 4/5y)
=2*4(1/5x + 1/5y)
= 8 (5y+5x/25xy)
Answer:
x=5.37 cm
Step-by-step explanation:
we know that
The volume of the box is
where
B is the area of the base of the box
h is the height of the box
<em>Box 1</em>
we have that
The area of the base is
The volume of the Box 1
is equal to
<em>Box 2</em>
we have that
The area of the base is
The volume of the Box 2
is equal to
![V_2=[(x+1)^2(x+2)]\ cm^3](https://tex.z-dn.net/?f=V_2%3D%5B%28x%2B1%29%5E2%28x%2B2%29%5D%5C%20cm%5E3)
![V_2=[(x^2+2x+1)(x+2)]\ cm^3](https://tex.z-dn.net/?f=V_2%3D%5B%28x%5E2%2B2x%2B1%29%28x%2B2%29%5D%5C%20cm%5E3)
Equate the equation of Volume 1 to the equation of Volume 2
Solve the quadratic equation by graphing
using a graphing tool
The solution is x=5.37 cm
see the attached figure
