Answer:
The least number of meals Amelia needs to cater in order to begin making profit = 38 meals.
Step-by-step explanation:
Given - Amelia runs a catering business. Based on her records, her weekly
profit can be modeled by P= -2x² + 152x - 150, where x is the
number of meals she caters and P is her profit. When P is negative,
Amelia losses money.
To find - What is the least number of meals Amelia needs to cater in order
to begin making profit.
Proof -
As given, P = -2x² + 152x - 150
Now,
Above the break-even point, she only get profit
The break -even point is a point where there is no profit, and no loss.
Now,
For break-even point,
![\frac{dP}{dx} = 0](https://tex.z-dn.net/?f=%5Cfrac%7BdP%7D%7Bdx%7D%20%3D%200)
⇒![\frac{d}{dx}( -2x^{2} + 152x - 150) = 0](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%28%20-2x%5E%7B2%7D%20%2B%20152x%20-%20150%29%20%3D%200)
⇒-4x + 152 = 0
⇒- 4x = - 152
⇒4x = 152
⇒x =
= 38
∴ we get
If Amelia caters at least 38 meals , then she makes Profit.
Answer:
6
Step-by-step explanation:
4 pairs of parallel lines
Answer:
4th Option, 45.1
Step-by-step explanation:
Cos(Ф) = ![\frac{12}{17}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B17%7D)
Ф = Cos⁻¹ (
)
Ф = 45.1
Hope this helps!