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3 years ago

What is y+2=⅞(x-3) in standard form?

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

8 0

Answer:

7x - 8y = 37

Explanation:

y+2 = ⅞(x-3) (distribute ⅞ -- x times 7/8, -3 times 7/8)

y+2 = ⅞x - 21/8 (subtract ⅞x from both sides)

y+2-⅞x = -21/8 (subtract 2 from both sides)

y-⅞x = -37/8 <--- result of -21/8 - 2

Multiply both sides by 8 to get ride of fractions

8y - 7x = -37 (rearrange)

-7x + 8y = -37

It's better to have a positive coefficient for x if you can. So multiply both sides by -1. That just means changing the sign of every term on both sides, you get

7x - 8y = 37

Tresset [83]3 years ago

3 0

The correct answer is 7x-8y=37

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Answer:

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vodomira [7]

Answer:

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