All categories

3 years ago

How do i solve this problem?

Mathematics

1 answer:

Pani-rosa [81]3 years ago

6 0

Area of a triangle = 1/2 x base x height

using the given information: area = 40 and base = 20

you now have 40 = 1/2 x 20 x height

divide both sides by 1/2

80 = 20 x height

divide both sides by 20

height = 80 / 20

height = 4 in.

You might be interested in

Please help with the problem below! Thank you

Gwar [14]

Answer:

$d \le -3$

Step-by-step explanation:

The given inequality is;

$\frac{d-3}{10} \ge \frac{2d+3}{5}+\frac{d+3}{3}$

Clear the fraction by multiply through by 30;

$3(d-3) \ge 6(2d+3)+10(d+3)$

Expand;

$3d-9\ge 12d+18+10d+30$

Group like terms;

$3d-12d-10d \ge 18+30+9$

$-19d \ge 57$

Divide through by -19 and reverse the sign.

$d \le -3$

6 0

4 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth.

Sphinxa [80]

Answer:

14.86854, or 15

Step-by-step explanation:

3 0

3 years ago

Which of the following expressions is equivalent to (3x+6)(2x-1)

Elden [556K]

Answer:

6x^2+9x-6

Step-by-step explanation:

(3x+6)(2x-1)=6x^2+12x-3x-6=6x^2+9x-6

4 0

3 years ago

what are two equivalent expressions to the following radical expression: (√10 to the 4th power x √12 to the 4th power) to the 8t

brilliants [131]

Answer:

(14400x^4)^8

Step-by-step explanation:

sqrt10 to the 4th is 10^2 or 100, and xsqrt12 to the 4th is 144x^4. Multiply these to get (14400x^4), and take the 8th to get (14400x^4)^8.

3 0

3 years ago

In Virginia, 120 lame dogs were tested for arthritis and Lyme disease. The results showed that 42 of the dogs had Lyme disease,

miskamm [114]

Answer:

The number of dogs that had both Lyme disease and arthritis is 18

Step-by-step explanation:

Let x represent dogs that have both Lyme disease and arthritis

Dog with only Lyme disease = 42 - x

Dog with only arthritis = 96 - x

The sum of the 3 category should give 120

x + (42 - x) + (96 - x) = 120

Collect like terms and solve

x - x - x + 42 + 96 = 120

-x + 138 = 120

138 - 120 = x

x = 18

Dog with only Lyme disease = 42 - x = 42 - 18 = 24

Dog with only arthritis = 96 - x = 96 - 18 = 78

Therefore, the number of dogs with both Lyme disease and anthritis is 18.

4 0

4 years ago