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leonid [27]
3 years ago
9

How do i solve this problem?

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0
Area of a triangle = 1/2 x base x height

using the given information: area = 40 and base = 20

you now have 40 = 1/2 x 20 x height

divide both sides by 1/2

80 = 20 x height

divide both sides by 20

height = 80 / 20

height = 4 in.


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The product of two numbers​
sladkih [1.3K]

Answer:

The product of two numbers is the result you get when you multiply them together. So 12 is the product of 3 and 4, 0 is the product of 4 and 5 and so on.

Step-by-step explanation:

4 0
3 years ago
I need help with the last 2 I need the next 3 in the sequence and the nth term ​
kkurt [141]

Answer:

f. the sequence goes by the half of the previous number.

= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...

g. the sequence goes by adding the consecutive odd number added to the previous number.

first number= 3.

second number= 3+3

= 6

third number= 6+5

= 11

fourth number= 11+7

= 18

fifth number= 18+9

= 27

sixth number= 27+11

= 38

seventh number= 38+13

= 51, etc.

= 3, 6, 11, 18, 27, 38, 51...

7 0
3 years ago
Give an example of a real number that is not rational.
Sever21 [200]

Answer:

A not rational number is called a irrational number btw. Anyway Some examples are √2 and pi.

7 0
2 years ago
NEED HELP ASP which of the following is an example of a mixed number?
AleksandrR [38]

d)

First choice is an improper fraction because you can't have 22 ninths.

And the second two are just normal fractions, not wholes.

The first choice would be the right answer IF instead of writing it like that, it was written like this ( 2 4/9 )

Your answer is d).

8 0
3 years ago
Read 2 more answers
Find the variance of this probability distribution. Round to two decimal places.​
attashe74 [19]

Answer:

Variance = 4.68

Step-by-step explanation:

The formula for the variance is:

\sigma^{2} =\frac{\Sigma(X- \mu)^{2}}{N} \\or \\ \sigma^{2} =\frac{\Sigma(X)^{2}}{N} -\mu^{2} \\

Where:

X: Values \\\mu: Mean \\N: Number\ of\ values

The mean can be calculated as each value multiplied by its probability

\mu = 0*0.4 + 1*0.3 + 2*0.1+3*0.15+ 4*0.05=1.15

\frac{\Sigma (X)^{2}}{N} =\frac{(0^{2}+1^{2}+2^{2}+3^{2}+4^{2})}{5} =6

Replacing the mean and the summatory of X:

\sigma^{2} = \frac{\Sigma(X)^{2}}{N} -\mu^{2} \\= 6 - 1.15^{2}\\= 4.6775

4 0
3 years ago
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