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3 years ago

How do i solve this problem?

Mathematics

1 answer:

Pani-rosa [81]3 years ago

6 0

Area of a triangle = 1/2 x base x height

using the given information: area = 40 and base = 20

you now have 40 = 1/2 x 20 x height

divide both sides by 1/2

80 = 20 x height

divide both sides by 20

height = 80 / 20

height = 4 in.

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Vera_Pavlovna [14]

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3 years ago

Read 2 more answers

Occasionally you may encounter an angle that's given in the old fashioned degrees/minutes/second form, as described in the box o

solniwko [45]

Answer:

$a=3.0881$ degrees.

$a=(0.017156)\pi$ rad or

$a=0.053897$ rad

Step-by-step explanation:

Let's start writing some equivalences.

1 degree = 60 minutes = 60'

1 minute = 1' = 60 seconds = 60''

Therefore,

1' = 60'' ⇒ 60' = 3600'' ⇒ 1 degree = 3600''

For a = 3 degree 5'17'' we are going to transform the minutes and the seconds into degrees.

60' = 1 degree ⇒

5' = $\frac{5}{60}$ degree

For the seconds :

3600'' = 1 degree ⇒

17'' = $\frac{17}{3600}$ degree

Finally :

$a=(3+\frac{5}{60}+\frac{17}{3600})$ degrees

$a=3.0881$ degrees.

For radians, the equivalence is :

360 degrees = 2π rad

For a = 3.0881 degrees ⇒

360 degrees = 2π rad

3.0881 degrees = $\frac{(3.0881)2\pi }{360}$ rad

$a=0.053897$ rad

or in terms of π ⇒ $a=(0.017156)\pi$ rad

7 0

3 years ago

#5 In *triangle* ABC, AB = 9 and BC = 15. What is the range the possible lengths for CA?<br> Why?

Naddika [18.5K]

CA must be in the range [15 - 9, 15 + 9] = [6, 24]
For the line segments to form a triangle the length of CA cannot be less the the difference between the other sides or greater than their sum.
At either extreme the three points A, B and C will be co-linear thus forming a triangle with area of zero

5 0

2 years ago

What percent of the June budget was for Tim's Chevron and car (to the nearest tenth)?

hjlf

Answer:

17.4% of the June budget was for Tim's Chevron and car.

Step-by-step explanation:

Consider the provided information.

Now consider the table shown in figure.

The total budget of June is $1695.

The sum of Tim's Chevron and Car is:

$23 + $272 = $295