N the figure, 2004-02-04-06-00_files/i0250000.jpg. If the ratio of the perimeter of to that of is 3:2 and the sum of the perimet
ers of the two triangles is 110, find the perimeter of each triangle. A.
perimeter of = 66
perimeter of = 44
B.
perimeter of = 73
perimeter of = 37
C.
perimeter of = 37
perimeter of = 73
D.
perimeter of = 44
perimeter of = 66
I assume you needed to add the diagram. However, I'll assume that we have triangle 1 and triangle 2 and solve the problem. You can then follow the same steps on the triangles you have. Let perimeter of triangle 1 be p1 and that of triangle 2 be p2
First, we know that the ratio between p1 : p2 is 3:2, this means that: p1/p2 = 3/2 p1 = (3/2) p2 .............> equation I
We also know that the sum of perimeters is 110, this means that: p1 + p2 = 110 .........> equation II
Substitute by equation I in equation II as follows: (3/2) p2 + p2 = 110 (5/2) p2 = 110 p2 = 44
Substitute by p2 in equation I to get p1 as follows: p1 = (3/2) (44) = 66
Therefore: perimeter of triangle 1 = p1 = 66 perimeter of triangle 2 = p2 = 44
