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Lady bird [3.3K]
3 years ago
14

A carpenter wants to cut on a board 16 1/2 feet in length into 1 7/8 feet pieces. How many pieces can be cut from the board?

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0
17 8/10 pieces that can be cut from the board
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The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri
Andrej [43]
FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
 For this case what we have is the following:
 For the two semicircles we can model it as a complete circle.
 We have to then:
 
 Perimeter: 
 P = 2 * pi * r
 or
 P = pi * d
 Where,
 r = radius
 d = diameter
 Therefore the perimeter is:
 P = 10 * pi
 For the largest circle we have:
 radius = 10
 Perimeter:
 P '= 2pi10
 P '= 20pi
 1/4 since 1/4 circle:
 P '' = 20pi / 4 = 5pi
 Then, the total perimeter of the source is:
 Pt = P + P '' = 10pi + 5pi = 15pi
 Pt = 15 * (3.141592)
 Pt = 47.1239
 round
 Pt = 47.1 ft

 Area:
 The total area will be:
 A = A (two semicircles) + A (quarter big circle)
 A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
 A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
 A = 98.17477042 feet ^ 2
 Round:
 A = 98.2 feet ^ 2

 Answer: 
 Perimeter of the source: 
 Pt = 47.1 ft 
 Area of the source: 
 A = 98.2 feet ^ 2

5 0
3 years ago
Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane
Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

a)

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36

b)

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

c)

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

Hence , this is the required solution .

4 0
3 years ago
How do animals breakedown rocks.
Hoochie [10]

Answer:

A,B

Step-by-step explanation:

It could be A or B because them stepping on a rock could cause the rock to crack and another could come along and do the same thing and the rock would eventually break.

4 0
3 years ago
Read 2 more answers
Harry fills up his Jeep with gasoline and notes that the odometer reading is miles. The next time he fills up his Jeep, he pays
lukranit [14]

Complete question :

Harry fills up his Jeep with gasoline and notes that the odometer reading is 23,568.7 miles. The next time he fills up his Jeep, he pays for 12.6 gallons of gasoline. He notes his odometer reading is 23,706.3 miles. How many miles per gallon did he get?

Answer:

10.9 miles per gallon

Step-by-step explanation:

Given that :

Odometer reading when filled up with gasoline = 23,568.7 miles

Odometer reading with 12.6 gallons of gasoline = 23,706.3 miles

Miles per gallon gotten :

(Current Odometer reading - reading when filled up) / gallon of gasoline

(23706.3 - 23568.7) / 12.6

= 10.920634

= 10.9 miles per gallon

6 0
2 years ago
ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!!<br> Do f(g(x)) and g(f(x))
bezimeni [28]

\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies&#10;\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}&#10;\\\\\\&#10;\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x


\bf \rule{34em}{0.25pt}\\\\&#10;g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}&#10;\\\\\\&#10;\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}&#10;\\\\\\&#10;\cfrac{5x}{5}\implies x


and in case you recall your inverses, when f(  g(x)  ) = x,  or g(  f(x)  ) = x, simply means, they're inverse of each other.

4 0
3 years ago
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