Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
1.= 2.4 Hours
2.= 8 miles per hour
3.= 150 miles per hour
Step-by-step explanation:
Answer:
15x + 20y
Step-by-step explanation:
First, we need to combine like terms,
10x + 20y + 5x
15x + 20y
Since x and y are different variables, we cannot combine them, meaning that the answer is,
15x + 20y
