0.4(2x+1/2)=3[0.2x+(-2)]-4

1 answer:

8 0

$0.4(2x+ \frac{1}{2})=3[0.2x+(-2)]-4 \\\\0.8 x+0.2= 0.6x-6-4 \\\\\0.8 x+0.2= 0.6x-10\\\\0.8x-0.6x=-10-0.2\\\\0.2x=-10.2\ \ / *10\\\\2x=-102\ \ / :2\\\\x=-51$

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