A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
C. PR and SQ have the same midpoing
Step-by-step explanation:
Equilateral triangle is a triangle with the 3 sides of the same length, and the 3 angles with the same measures/degree.
The formula to find the area of a triangle is base x height/2 , you do have the base (40), but you need the height. To find the height of an equilateral triangle you use the formula: side/2 x radical3, this way u'll find the height and therefor can calculate the area of the triangle.
Hope that helped :)
Answer:
Step-by-step explanation:20
20 130 3 8.12
- 1)
2:2 12-1 21=-11 # 1 - 2
1212
II + 3)
472
I + 3 2(1 - 1)
-1 2:2
3(12 - 1)
32 – 23– 3+.
Answer:
Step-by-step explanation:
A(1,7); B(-3,-1); slope m =(-1-7)/-3-1) = -8/-4 = 2
Equation of a line AB is
((y-y1) = m(x-x1)
y - 7 = 2(x-1)
y - 7 = 2x-2
y = 2x + 5
