WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!! (image attatched)

Please help been stuck on this for awhile

MakcuM [25]

Answer:

1. F (the row has 1164, the four-digit number with the least value)

2.

3. K (985 is the greatest 3-digit number)

4. J (67176 is the palindrome with the greatest number of digits)

5. K (3579 is the greatest number of odd numbers in counting order)

Step-by-step explanation:

I couldn't find an answer to number 2, sorry! You should probably go over it one more time and check that all these answers are correct. You might catch something I missed :)

Hope this helps!

8 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

2 years ago

9 + (-8) using a number line

Lelu [443]

Answer:

9 + (-8) = 1

Step-by-step explanation:

4 0

2 years ago

What was edwin average rate of jogging in miles per hour

Svetach [21]

Answer:Edwin average rate of jogging in miles per hour is

2 miles per hour

At the end of 30 min Edwin completed the track 3 times before Jose.

Step-by-step explanation:

Hope this helps

6 0

3 years ago

What are the measures of the angles in the triangle? (6x + 10) (x + 17) (4x - 34)

REY [17]

I'm not quite sure these are right. You might wanna check with a classmate or something first.

Step-by-step explanation:

(6x + 10) + (x + 17) + (4x - 34) = 180

11x - 7 = 180

11x = 173

x = 15.73 (answer had repeating decimal so i rounded up in the hundredths place)

(6x + 10)

6 (15.73) + 10

94.38 + 10

104.38

(x + 17)

(15.73) + 17

32.73

(4x - 34)

4(15.73) - 34

62.92 - 34

28.92

7 0

3 years ago