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Nesterboy [21]
3 years ago
12

WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!! (image attatched)

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0
The answer would be the first one
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If x is increased by 25% then, by what % is x² increased
Alinara [238K]

By <em>analytical</em> methods and <em>algebraic</em> handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

<h3>How to determine the percentage increase rate </h3>

In this case we have a <em>linear</em> variable x, whose increase is described by the following expression:

y = x · (1 + r/100)     (1)

Where r is the <em>increase</em> rate.

If we square (1), then we find that:

y² = x² · (1 + r/100)² = (1 + r'/100)     (2)

Where r' is the <em>equivalent increase</em> rate.

(1 + r/50 + r²/10000) = (1 + r'/100)

r'/100 = r/50 + r²/10000

r' = r/2 + r²/100

If we know that r = 25, then the equivalent increase rate is:

r' = 25/2 + 25²/100

r' = 18.75

By <em>analytical</em> methods and <em>algebraic</em> handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

To learn more on percentages: brainly.com/question/14979505

#SPJ1

5 0
2 years ago
A company launches two new products. The market price, in dollars, of the two products after a different number of years, x, is
Inga [223]

Answer: prodcut 2 because the function is exponential

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3y-4=6-2y<br> How do I solve this
KIM [24]

Answer:

solve the 3y and 2y first

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Ratios - we need help!
Deffense [45]

12:36 for the first one

6:21 for the second one

And 21:15 because let's say that for every 7 cans that a group gets , the other group gets 5

8 0
3 years ago
Express in terms of trig functions of single x : (sin2x+cos2x)^2
RSB [31]

(\sin 2 x+\cos 2 x)^{2}=1+\sin 4 x

Solution:

Given trigonometric function:

(\sin 2 x+\cos 2 x)^{2}

Using perfect square formula:

(a+b)^{2}=a^{2}+2 a b+b^{2}

a=\sin 2 x, b=\cos 2 x

(\sin 2 x+\cos 2 x)^{2}=\sin ^{2}(2 x)+2 \sin 2 x \cos 2 x+\cos ^{2}(2 x)

Arranging square terms together.

                           =\sin ^{2}(2 x)+\cos ^{2}(2 x)+2 \sin 2 x \cos 2 x

Using the trigonometric identity: \sin ^{2}x+\cos ^{2}x=1

                           =1+2 \cos 2 x \sin 2 x

Using the trigonometric identity: 2 \cos   \sin x=\sin 2 x

                          =1+\sin (2 \cdot 2 x)

                          =1+\sin 4 x

Hence (\sin 2 x+\cos 2 x)^{2}=1+\sin 4 x.

6 0
3 years ago
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