At least you can write it as the sum of half of it twice, that is:
2/x = 1/x + 1/x
whatever x number you have, for example:
2/5 = 1/5 + 1/5
But then, you can express a fraction in many different ways, for example again:
2/5 = <span>1/5 + 1/5 = 2/10 + 2/10
</span>= 1/10 + 1/10 + 1/10 + 1/10
so there are an infinite ways of expressing such a fraction.
The value of a=9,b=3 and c=1
Step-by-step explanation:
The graph shown is for function f(x)
The given function is f(x)=
Table says,
X Y
-2 a
1 b
0 c
1 (1/3)
2 (1/9)
To find value of a:
From table, for output value a, input value, x=(-2)
we can write f(-2)=a
Therefore,
f(x)=
f(-2)=
a=
a=
a=9
To find value of b:
From table, for output value a, input value, x=(-1)
we can write f(-1)=b
Therefore,
f(x)=
f(-1)=
b=
b=
b=3
To find value of c:
From table, for output value a, input value, x=(0)
we can write f(0)=c
Therefore,
f(x)=
f(0)=
c=
c=1
Answer:
21,000
Step-by-step explanation:
This is more of straightforward multiplication, so I cannot explain much! If you want me to try to do more, then just comment.
(7 * 10 * 5) * (3 * 10 * 2)
= (70 * 5) * (30 * 2)
= (350) * (60)
= 21,000
Thusly, in standard form, the equation given is
.
Hope this helps! (:
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is

where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A

We do the same for company C

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A
We could do it by first writing

so that

and since
, we have

# # #
Alternatively, we can just compute the product and take it mod 4:

and so we get the same result of 1.