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agasfer [191]
3 years ago
7

What is the equation of the line that passes through (1, 2) and (8,9) in slope-intercept form?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

The equation of line that passes through (1, 2) and (8,9) in slope-intercept form is: y = x+1

Step-by-step explanation:

The slope-intercept form of line is given by the formula:

y = mx+b

Here m is the slope and b is the y intercept

Given

(x_1,y_1) = (1,2)\\(x_2,y_2) = (8,9)

First of all, the slope has to be found

m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{9-2}{8-1}\\m = 1

Putting m=1 in the equation

y = x+b

Putting the point (1,2) in the equation to find the value of b

2 = 1+b\\b = 2-1\\b = 1

The equation is:

y = x+1

Hence,

The equation of line that passes through (1, 2) and (8,9) in slope-intercept form is: y = x+1

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chubhunter [2.5K]

Answer:

90

Step-by-step explanation:

600(.15) = 90

8 0
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A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
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So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
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For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
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and Probability of getting 4 successes (or more) 
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So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
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Answer:

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Then time 9 by 3 as 3*(4) is 12

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