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4 years ago

Graph the six terms of a finite series where a1 = -3 and r = 1.5.

Mathematics

2 answers:

zloy xaker [14]4 years ago

6 0

The verified answer is D.

zavuch27 [327]4 years ago

4 0

A1 is the 1st term
r is the difference, they can say "r" or "d" for the difference

1st a1 is the first term = -3
2nd "r" is the difference between each consecutive terms (coming after each other) = 1.5
the rule to get any term of the sequence as we add 1.5 each time is --> a1+(n-1)*d
a1 --> 1st term , n --> order of the term u want whether 2nd, 3rd , 25th
d --> difference
so to get the 2nd--> -3+(2-1)*1.5= -1.5
to get the 3rd --> -3 +(3-1)*1.5 = 0
<span>and so on </span>

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Mariulka [41]

Answer:

first, find the area of the circle cut.

r= 3 feet

π=3.14

area of a circle= πr²= 3.14×3×3= 28.26 sq.feet

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area of rectangle = l×b

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area= 16×14= 224 sq. feet

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3 years ago

How do you simplify the radical: square root of 28

Lilit [14]

Answer:

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Step-by-step explanation:

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3 years ago

Q and r are independent events. if p(q) = 1/4 and p(r)=1/5, find p(q and r)

klasskru [66]

Answer:

(b) $\frac{7}{30}$

Step-by-step explanation:

When two p and q events are independent then, by definition:

P (p and q) = P (p) * P (q)

Then, if q and r are independent events then:

P(q and r) = P(q)*P(r) = 1/4*1/5

P(q and r) = 1/20

P(q and r) = 0.05

In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.

In the first ballot box there are 9 balls, 3 white and 6 yellow.

Then the probability of obtaining a white ball from the first ballot box is:

$P (W_{u_1}) = \frac{3}{9} = \frac{1}{3}$

In the second ballot box there are 10 balls, 7 white and 3 yellow.

Then the probability of obtaining a white ball from the second ballot box is:

$P (W_{u_2}) = \frac{7}{10}$

We want to know the probability of obtaining a white ball in both urns. This is: P( $W_{u_1}$ and $W_{u_2}$ )

As the events are independent:

P( $W_{u_1}$ and $W_{u_2}$ ) = P ( $W_{u_1}$ ) * P ( $W_{u_2}$ )

P( $W_{u_1}$ and $W_{u_2}$ ) = $\frac{1}{3}* \frac{7}{10}$

P( $W_{u_1}$ and $W_{u_2}$ ) = $\frac{7}{30}$

Finally the correct option is (b) $\frac{7}{30}$

3 0

3 years ago

A bank loaned out $68,000, part of it at the rate of 13% per year and the rest at a rate of 5%per year. If the interest received

marin [14]

Answer: $31000 was loaned at 13%.

Step-by-step explanation:

Let x represent the amount loaned out at 13% interest rate.

Let y represent the amount loaned out at 5% interest rate.

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x + y = 68000

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13/100 × x = 0.13x

The interest received made from $y in one year is

5/100 × x = 0.05y

If the interest received was $5880, it means that

0.13x + 0.05y = 5880- - - - - - - - - 1

Substituting x = 68000 - y into equation 1, it becomes

0.13(68000 - y) + 0.05y = 5880

8840 - 0.13y + 0.05y = 5880

- 0.13y + 0.05y = 5880 - 8840

- 0.08y = - 2960

y = - 2960/- 0.08

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x = $31000

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3 years ago

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ANEK [815]

Answer:

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3 years ago