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ioda
3 years ago
15

There are 12 state quarters and 5 regular quarters in a jar. Charles randomly picks up a quarter, puts it back in the jar, and t

hen picks another quarter without looking. Which tree diagram shows the correct probabilities for this situation? WILL GIVE BRAINLIEST!!!
PLEASE HELP NEED NOW!!!

Mathematics
2 answers:
Arisa [49]3 years ago
6 0
Its the first picture all the way to the left.
Sphinxa [80]3 years ago
6 0

the first picture is the correct answer

total number of coins in the jar = 17

number of state quarters = 12

number of regular quarters = 5

Probability = favorable outcomes / total outcomes

Probability of picking a state quarter = 12/17

Probability of picking a regular  quarter = 5/17

As he puts the coin back in the jar after the first pick up, the total number of coins in the jar remains the same =17

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X+2(x+3(x+4(x+5)))=153
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Answer:

x=1

Step-by-step explanation:

Here first open the inner parentheses and use the distributive property,

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2 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
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\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
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\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
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\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
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with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad 
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&\quad \uparrow \\
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\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
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Answer:

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Step-by-step explanation:

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Answer:

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