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4 years ago

If RT is a diameter of Q, Find m A.88° B.89° C.92° D.101°

Mathematics

1 answer:

kumpel [21]4 years ago

7 0

Answer:

A.88°

Step-by-step explanation:

Given,

RT is the diameter of the circle with center Q.

We have to find the measure of ∠RQS.

Solution,

$m\angle RQS=7x+18\ \ \ and\\m\angle TQS=9x+2$

Since RT is the diameter. That is it makes a straight angle at the center Q.

And measure of straight angle is 180°.

So we can say that ∠RQS and ∠SQT makes a straight angle.

$\therefore \angle RQS+\angle SQT=180\°$

Now substituting the given values, we get;

$(7x+18)+(9x+2)=180\°\\\\7x+9x+20=180\°\\\\16x=180-20=160\°\\\\x=\frac{160}{16}=10\°$

We get the value of 'x'.

By substituting the value of x, we can find the measure of ∠RQS.

$m\angle RQS=7x+18=7\times10+18=70+18=88\°$

$m\angle TQS=9x+2=9\times10+2=90+2=92\°$

Hence the measure of ∠RQS is 88°.

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3 years ago

The selling price of a refrigerator, is $739.20. If the mark up is 20% of the dealers cost , what is the dealers cost of the ref

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3 years ago

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yarga [219]

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Note: For this problem we use the calculator on degrees

For this case we need to remember this identity :

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For this case if we apply for our desired formula we got this:

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