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makvit [3.9K]
4 years ago
15

If RT is a diameter of Q, Find m A.88° B.89° C.92° D.101°

Mathematics
1 answer:
kumpel [21]4 years ago
7 0

Answer:

A.88°

Step-by-step explanation:

Given,

RT is the diameter of the circle with center Q.

We have to find the measure of ∠RQS.

Solution,

m\angle RQS=7x+18\ \ \ and\\m\angle TQS=9x+2

Since RT is the diameter. That is it makes a straight angle at the center Q.

And measure of straight angle is 180°.

So we can say that  ∠RQS and ∠SQT makes a straight angle.

\therefore \angle RQS+\angle SQT=180\°

Now substituting the given values, we get;

(7x+18)+(9x+2)=180\°\\\\7x+9x+20=180\°\\\\16x=180-20=160\°\\\\x=\frac{160}{16}=10\°

We get the value of 'x'.

By substituting the value of x, we can find the measure of ∠RQS.

m\angle RQS=7x+18=7\times10+18=70+18=88\°

m\angle TQS=9x+2=9\times10+2=90+2=92\°

Hence the measure of ∠RQS is 88°.

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