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Rama09 [41]
3 years ago
10

Escribe un decimal que sea 1/10 de 3.0

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0
Un decimal que es 1/10 de 3,0 es 0,3
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liubo4ka [24]
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What does this mean?
katrin2010 [14]

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A baseball player hits a pitched ball when it is 4 ft above the ground. The initial upward velocity is 80 ft/s. How
iren [92.7K]

Answer:

t=+4.06

Step-by-step explanation:

when the baseball hits the ground, the height will be 0.

h=0we are given that h=−16t2+64t+4.

this means that the height is 0 when −16t2+64t+4=0.−16t2+64t+4=0divide both sides by 4:−4t2+16t+1=04=0−4t2+16t+1=0 can be solved using the quadratic formula:t=−b±√b2−4ac2a, where at2+bt+c=0.at2+bt+c=−4t2+16t+1a=−4,b=16,c=1t=−b+√b2−4ac2aor−b−√b2−4ac2a−b+√b2−4ac2a=−16+√272−8=−0.06..−b−√b2−4ac2a=−16−√272−8=4.06 (3s.f.)we have 2 values for t:−0.06 and 4.06.

since time cannot be negative, only the positive value can be taken.

this is 4.06, to 3 significant figures.the time taken is 4.06 seconds.

7 0
2 years ago
The universal ga law PV=net describes the relationship among the pressure volume and temperature of a gas.
miskamm [114]

Answer:

R ≈ 8.31

Step-by-step explanation:

Filling in the given values ...

... pV = nRT

... 2·4.155 = 1·R·1

... 8.31 = R

7 0
3 years ago
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
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