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saw5 [17]
3 years ago
5

Describe how you will subtract to find the difference of 604-357

Mathematics
2 answers:
Allushta [10]3 years ago
7 0
Just subtract 604 from 357 and you’ll get 247 after y can check ur work by just adding 247 and 357 which will equal 604 so u know u got the right answer
Elza [17]3 years ago
6 0

Answer:

just subtract it

Step-by-step explanation:

604-357=247

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Pleas help it’s due tomrrow
katovenus [111]

Answer:

Step-by-step explanation:

K is located at -25

L is located at -15

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hope this helps <3

5 0
3 years ago
RS=4y+4, ST=3y+4, and RT=43 <br> What is the value of y?
Shkiper50 [21]

The value of y is 5

<h3>How to determine the value </h3>

From the given line, it can be concluded that:

The segment RT is divided into RS and ST

But we have the following parameters

The length of the sides are:

  • RS=4y+4
  • ST=3y+4
  • RT=43

Since RT is RS added to ST:

We have;

RT = RS + ST

substitute the values

43 = 4y + 4 + 3y + 4

collect like terms

43 = 4y + 3y + 4 + 4

Add like terms

43 = 7y + 8

43 = 7y + 8

Make '7y' subject of formula

7y = 43 - 8

7y = 35

Make 'y' the subject of formula

y = 35/ 7

y = 5

Thus, the value of y is 5

Learn more about segments here:

brainly.com/question/2437195

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5 0
2 years ago
What is the distance from X to Y?
densk [106]

Answer:

15

Step-by-step explanation:

distance formula

\sqrt{((x2-x1)^2 + (y2-y1)^2)}

\sqrt{(9-0)^2 + (-6-6)^2}

\sqrt{81 + 144}

\sqrt{225}

15

7 0
2 years ago
Use the image below to answer the following question. Find the value of sin x® and cos yº What relationship do the ratios of sin
Flauer [41]

Answer:

sin(x) and cos(y) are equal and have ratio of 1 : 1

First find the missing hypotenuse using Pythagoras theorem:

a² + b² = c²

12² + 5² = c²

c = √144+25

c = 13

using sine rule:

sin(x) = \dfrac{opposite}{hypotenuse}

sin(x) = \dfrac{5}{13}

using cosine rule:

cos(y) = \dfrac{adjacent}{hypotenuse}

cos(y) = \dfrac{5}{13}

4 0
2 years ago
Read 2 more answers
Find the GCF.<br> 6m3n and 8mn2
Liono4ka [1.6K]

Answer:

2mn

Step-by-step explanation:

6m^3n,\:8mn^2

Find the GCD of 6,\:8:

6

=2\cdot \:3

8

=2\cdot \:4

=2\cdot \:2\cdot \:2

So the prime factor common to 6, 8 is:

2

So the factor common to 6m^3n,\:8mn^2:

=2mn

6 0
3 years ago
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