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sergeinik [125]
3 years ago
5

Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

Mathematics
2 answers:
murzikaleks [220]3 years ago
6 0

(0, –2) is correct

hopes i helps

alekssr [168]3 years ago
3 0

We are given coordinates of a continuous function f(x)

(–2, 0)

(0, –2)

(2, –1)

(4, 0).

We need to find the possible turning point for the continuous function.

<u>Note: Turning point is a point on the graph where slope of the curve changes from negative to positive or positive to negative.</u>

<em>A turning point is always lowest or highest point of the curve (where bump of the graph seen).</em>

For the given coordinates we can see that  (–2, 0) and (4, 0) coordinates are in a same line, that is on the x-axis.

But the coordinate  (0, –2) is the lowest point on the graph.

Therefore, (0, –2) is the turning point for the continuous function given.


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Answer:

See below ↓↓

Step-by-step explanation:

<u>Finding the radius</u>

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  • r = 3.98 cm ≅ 4 cm

<u />

<u>Surface Area</u>

  • 4πr²
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<u></u>

<u>Volume</u>

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4 0
2 years ago
Four divided by blank equals 24 what is the answer ??
MArishka [77]
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8 0
3 years ago
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Karina is creating two pyramids with the nets below using construction paper. In both nets, all of the triangular faces of the p
sleet_krkn [62]

Answer:

144 sq in

Step-by-step explanation:

Face height=9, bases=6 in

#Assume the pyramid has a square base.

First we need to calculate the perpendicular height of the pyramid:

#Pythagorean \ Theorem\\a^2+b^2=c^2\\9^2-(0.5\times 6)^2=h^2\\72=h^2\\h=\sqrt{72} \ in

Now to find the surface area of each pyramid:

A=lw+l\sqrt{(w/2)^2+h^2}+w\sqrt{(l/w)^2+h^2}\\\\\#w=l=6,h=\sqrt{72}\\\\A=6^2+6\sqrt{(6/2)^2+72}+6\sqrt{(6/6)^2+72}\\\\A\approx 144\ sq \ in

Hence amount of construction paper needed to make each pyramid is 144 sq in

3 0
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bagirrra123 [75]

Answer:

4

Step-by-step explanation:

7 0
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What percentage is represented by the diagram bellow?
sergey [27]

Answer:

c. 130%

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the first box is 100%

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6 0
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