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In-s [12.5K]
3 years ago
6

Sketch a line passing through the point and having slope m. (0,6), m=-3

Mathematics
2 answers:
Ber [7]3 years ago
7 0
\bf slope = {{ m}}= \cfrac{rise}{run}\implies -3\implies \cfrac{-3}{1}
\qquad \qquad \qquad 
\left( \stackrel{run}{0}~,~\stackrel{rise}{6} \right)

now, to graph a LINE, all you need is two points, so, you already have one, 0,6.

to get a second point, simply apply the rise and run values, so 0+1 = 1 and 6 -3 = 3, thus there's your second point, (1, 3), graph it away.
DochEvi [55]3 years ago
4 0
Y= -3x+b
6=b

The answer is y=-3x+6
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Allushta [10]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
finlep [7]

Answer:

Part a) The elevation of the road is 6\°

Part b) The rise is 0.2\ km

Step-by-step explanation:

Part a) What is the elevation of the road to the nearest degree?

Let

y-----> the rise of the road ( vertical distance)

x ----> the run of the road (horizontal distance)

we have

y/x=1/10

we know that

The ratio y/x is equal to the tangent of the angle of the elevation of the road

Let

\theta ---->  angle of the elevation of the road

tan(\theta)=y/x

tan(\theta)=1/10

\theta=arctan(1/10)=6\°

Part b)  If the road is two km long, how much does it rise?

using proportion

1/10=y/2

y=2/10=0.2\ km

3 0
3 years ago
the midpoint of kl is m(4.8, -7.8). one endpoint is l(0.6, -5.6). find the coordinates of the other endpoint k.
Vera_Pavlovna [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&k&(~ x &,& y~) 
%  (c,d)
&l&(~ 0.6 &,& -5.6~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)

\bf \left( \cfrac{0.6+x}{2}~~,~~\cfrac{-5.6+y}{2} \right)~=~\stackrel{midpoint}{(4.8~,~-7.8)}\quad 
\begin{cases}
\cfrac{0.6+x}{2}=4.8\\\\
0.6+x=9.6\\
\boxed{x=9}\\
---------\\
\cfrac{-5.6+y}{2}=-7.8\\\\
-5.6+y=-15.6\\
\boxed{y=10}
\end{cases}
8 0
3 years ago
How write 89,170,326 in expanded and
evablogger [386]

80,000,000+9,000,000+100,000+70,000+300+20+6

8 0
4 years ago
Read 2 more answers
The table shows the profit from a school book fair based on the number of books sold. What is the rate of change for the functio
dsp73

You are given a table

\begin{array}{cc}\text{Number of books sold} & \text{Profit}\\100 & \$50\\250 & \$275\\300 & \$350\\350 & \$450\end{array}

The rate of change for the function represented in the table can be calculated using the formula

\dfrac{y_{i+1}-y_i}{x_{i+1}-x_i},

where i=1,2,3.

1. When i=1,

\dfrac{y_2-y_2}{x_2-x_1}=\dfrac{275-50}{250-100}=\dfrac{225}{150}=1.5

2. When i=2,

\dfrac{y_3-y_2}{x_3-x_2}=\dfrac{350-275}{300-250}=\dfrac{75}{50}=1.5

3. When i=3,

\dfrac{y_4-y_3}{x_4-x_3}=\dfrac{425-350}{350-300}=\dfrac{75}{50}=1.5

Then the rate of change is $1.5

Answer: correct choice is D.

5 0
3 years ago
Read 2 more answers
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