If <em>X</em> is uniformly distributed on the interval (0, 12), then its PDF is

or simply

and the zero-elsewhere case is assumed.
Whether you include 0 and 12 in the domain is irrelevant, since the probability that <em>X</em> = 0 or <em>X</em> = 12 are both zero.
4➡ tens
3 ➡ ones
----------------
2➡tenths
4➡hundredths
5➡ thousandths
Anything behind the decimal point ends with a "ths" ("th" )
So, the value of "5" might be 'thousandths'
Answer:
If solving for y: y = 8 - 2x
If solving for x: x = 
Step-by-step explanation:
<u>To solve for y:</u>
Factor out the common term, which in this case is 3.
3(2x + y) = 24
Divide both sides by 3.
2x + y = 
Simplify
to 8.
2x + y = 8
Subtract 2x from both sides.
y = 8 - 2x
<u>To solve for x: </u>
Factor out the common term, which in this case is 3.
3(2x + y) = 24
Divide both sides by 3.
2x + y = 
Simplify
to 8.
2x + y = 8
Subtract y from both sides.
2x = 8 − y
Divide both sides by 2.
x = 