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prisoha [69]
3 years ago
11

Sixty- four and five hundred eleven thousandths in standard form

Mathematics
1 answer:
skad [1K]3 years ago
3 0

Sixty- four and five hundred eleven thousandths in standard form

64.511

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If you shift the quadratic parent function, f(x)=x^2, right 12 units, what is the equation of the new function?
Kobotan [32]

Answer:

f(x)=(x-12)^2

Step-by-step explanation:

We know that the function f(x+m) equals to the function f(x) translated 'm' times to the left. Therefore, to translate the function f(x) = x^2 twelve units to the right, we have to:

f(x-12) = (x-12)^2

Therefore, the new function is: f(x)=(x-12)^2

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Step-by-step explanation:

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3 years ago
Given: ⅓ (18x + 27) = 81 Prove: x = 12
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Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

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Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

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