Together, what do the divisions of the DHSMV do?

Templates are created to define the basic structure of any document which is repeated and the user need not do those designs from the scratch.

Normally a template will contain pre-defined formula, formatting. But it will not contain data because, the purpose of template is that the structure will be same but the value may differ and the template should react according to the data.

So any template will contain design except data. We can use existing template / default template or even create a new one.

4 0

2 years ago

Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program

Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

.data

sourceword:

.word 0xAB

wordmask:

.word 0xCF

operand:

.long 0xAA

.text

.globl _start

_start:

movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)

movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)

xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)

andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)

orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)

xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)

movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)

movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)

movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)

shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)

# 0x000000AA=00000000000000000000000010101010

# =>00000000000000000000010101010000=0x00000550.

rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)

# 0x000000AA=00000000000000000000000010101010

3 =>10100000000000000000000000001010= 0xA000000A.

sarl %ecx # here the count value to shift the bits not mentioned.

# It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.

See more about logic program at brainly.com/question/14970713

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5 0

1 year ago

Gregor installed a third stick of known-good RAM into his Core i7 system, bringing the total amount of RAM up to 3 GB. Within a

MA_775_DIABLO [31]

Answer:

The speed or quality was different.

Explanation:

The new ram that he installed most likely had a different rate, or was a different quality than the old ram.

5 0

2 years ago