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kenny6666 [7]
3 years ago
14

Describe an ergonomic consideration for your body while working for long periods in front of a monitor or computer screen?

Computers and Technology
1 answer:
cestrela7 [59]3 years ago
4 0
Getting an ergonomic keyboard
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Write a function that checks whether two words are anagrams. Two words are anagrams if they contain the same letters. For exampl
Masteriza [31]

Answer:

def isAnagram(s1, s2):

   list1=s1

   list2=s2

   sortedlist1 = sorted(list1)

   sortedlist2 = sorted(list2)

   if sortedlist1 == sortedlist2:

       print(list1+ " and "+list2+ " are anagram")

   else:

       print(list1+ " and "+list2+ " are not anagram")

Explanation:

Here is a call to the function isAnagram():

list1 =input("Enter String1 ")

list1 =input("Enter String2 ")

isAnagram(list1,list2)

Attached is the run and output for this program

4 0
3 years ago
Computer-generated color images of the brain that provide information about brain activity and glucose metabolism are produced b
frozen [14]

The answer to this question is the PET scan. Positron Emission Tomography or PET scan is an imaging test that checks and trace for diseases in the body. This also shows how the body organs is functioning / working. The doctor can evaluate the function of the patients body by the 3D color images produced by the PET Scan.  

4 0
3 years ago
How do you keep word from trying to capitalize every isolated letter "i"
Firdavs [7]
Write "i" the write random words then delete it and add the lowercase i
8 0
3 years ago
Read 2 more answers
¿Cuáles son los 5 Procesadores de textos on line más usados?
labwork [276]

Answer:

5 Procesadores de textos

Explanation:

Google Docs.

Textilus - Edición Microsoft Word.

TextEdit.

Kingsoft Office Writer.

Páginas.

8 0
3 years ago
A 4-way set associative cache has 64 blocks of 16 words. How many bits are there in the ""tag"" field of the 15-bit address for
Tanya [424]

Answer:

3 bits

Explanation:

Given a 4- way set associative cache that has 64 blocks of 16 words.

Therefore, the number of sets cache has:

\frac{64}{4} = 16

Now,

Cache data size is 16kB

The number of cache blocks can be calculated as:

16kB/16 = 1024 bytes/16 byte\times 16 = 256 cache blocks

Now,

Total sets = \frac{cache blocks}{associative sets}

Total sets = \frac{256}{4} = 64

Now,

2^{n} = 64

n = 6

For 15 bit address for the architecture, the bits in tag field is given by:

15 - (6 + 6) = 3 bits

Thus the tag field will have 3 bits

6 0
3 years ago
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