Answer:

Step-by-step explanation:
In the given right triangle,
Measure of angle = x°
Opposite side of the angle = 12 units
Adjacent side of the angle = 6 units
By taking tangent ratio of the given angle,
tan(x°) = 
= 
= 2



Answer:
30
Step-by-step explanation:
The midpoint of BC will be a distance from line k that is the average of the distances of B and C: (17+13)/2 = 15. Call that midpoint P. We know distance MP is half of distance MA. This same relationship will hold with respect to the distances from P and A to any line through M. That is, the distance from line k (through M) is twice the distance from P to line k: 30 units.
Ok but allow my humble self to use
instead of
.
We have,

If you wanna know what the inverse is swap the values of x and y,

And now solve for y,
.
Hope this helps.
Answer: (X,Y) = (0.4, 7.75)
Step-by-step explanation:
Y=7.75,
19.375X=7.75
Then solve for X
Divide 19.375 on both sides to get X=0.4
Y=7.75
X=0.4